The quadrilateral ABCD is shown in the co-ordinate diagram below - Junior Cycle Mathematics - Question 11 - 2021
Question 11
The quadrilateral ABCD is shown in the co-ordinate diagram below.
(a) Complete the table below to show the co-ordinates of the four corners of ABCD.
Point A ... show full transcript
Worked Solution & Example Answer:The quadrilateral ABCD is shown in the co-ordinate diagram below - Junior Cycle Mathematics - Question 11 - 2021
Step 1
Complete the table below to show the co-ordinates of the four corners of ABCD.
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Answer
The co-ordinates for points A, B, C, and D are as follows:
A (2, 4)
B (2, 0)
C (8, 0)
D (8, 4)
Step 2
On the diagram above, draw the image of ABCD under axial symmetry in the x-axis.
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Answer
To draw the image of ABCD under axial symmetry in the x-axis, reflect each point over the x-axis:
A (2, 4) becomes A' (2, -4)
B (2, 0) becomes B' (2, 0)
C (8, 0) becomes C' (8, 0)
D (8, 4) becomes D' (8, -4)
Plot these points on the diagram.
Step 3
Work out the area of the shape ABCD.
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Answer
To find the area of quadrilateral ABCD, it can be divided into a rectangle and a triangle.
Rectangle ABCD:
Length = |x_D - x_A| = |8 - 2| = 6
Height = |y_A - y_B| = |4 - 0| = 4
Area = Length × Height = 6 × 4 = 24
The area of the rectangle ABCD is:
Area = 24 square units.
Step 4
Write each line segment from the list above into the correct place in the table below, to match each line segment to its equation.
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Answer
The equations corresponding to each line segment are as follows:
[AB]: y = 4 (horizontal line at y = 4)
[BC]: y = 0 (horizontal line at y = 0)
[CD]: y = x - 7 (diagonal line segment)
[AD]: x = 8 (vertical line at x = 8)
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