Ray is fitting draught excluders around the outside of one of his windows - Junior Cycle Mathematics - Question 10 - 2014

To find the length (circumference) of the semicircle, we can use the formula for the circumference of a circle and take half of it:

$ext{Circumference} = 2 ext{π}r$

For the semicircle:

ext{Length} = rac{1}{2}(2 ext{π} imes 0.6)

Calculating this gives:

$= 0.5 imes (2 imes ext{π} imes 0.6) \\ = 1.88 ext{ m (correct to two decimal places)}$

To find the perimeter of the window, we need to add the length of the rectangle to the length of the semicircle and the diameter of the semicircle:

$ext{Perimeter} = ext{Length of the rectangle} + ext{Length of the semicircle} + ext{Diameter}$

Substituting the values:

$= 1.5 + 1.88 + 1.2 \\ = 4.58 ext{ m (correct to two decimal places)}$

Thus, the perimeter of Ray's window is 4.58 metres.