A closed rectangular box has a square base with sides of length 3 cm, and a height of 5 cm - Junior Cycle Mathematics - Question 3 - 2017

To complete the net, we need to include all the rectangles that make up the box. The net will consist of:

• 2 rectangles of dimensions 3 cm x 5 cm (the sides)
• 1 rectangle of 3 cm x 3 cm (the base)
• 1 rectangle of 3 cm x 5 cm (the top)

The arrangement can follow that of a cross, ensuring that every face of the box is represented.

Make sure to arrange the rectangles such that they are correctly oriented and can fold to form the box.

To find the volume of the candle, which is in the shape of a cylinder, we use the formula:

$V = \pi r^2 h$

Where:

• $r$ is the radius of the cylinder
• $h$ is the height of the cylinder

Given that the height $h = 4 \text{ cm}$ and the radius $r$ can be taken as $1 \text{ cm}$:

Substituting into the formula:

$V = \pi (1)^2 (4)$ $V = 4\pi$

Using the approximation $\pi \approx 3.14$:

$V \approx 4 \times 3.14 = 12.56 \text{ cm}³$

Rounding to the nearest cm³, the volume of the candle is approximately $13 \text{ cm}³$.