Photo AI

The following is part of a bus timetable from Galway to Limerick - Junior Cycle Mathematics - Question 5 - 2018

Question icon

Question 5

The-following-is-part-of-a-bus-timetable-from-Galway-to-Limerick-Junior Cycle Mathematics-Question 5-2018.png

The following is part of a bus timetable from Galway to Limerick. Galway depart 06:40 07:20 07:50 Oranmore depart 06:48 07:28 07:57 Gort depart 07:36 08:16 08:45 En... show full transcript

Worked Solution & Example Answer:The following is part of a bus timetable from Galway to Limerick - Junior Cycle Mathematics - Question 5 - 2018

Step 1

What is the latest time that James can get the bus from Oranmore?

96%

114 rated

Answer

James needs to be in Limerick by 09:30. The latest bus from Oranmore arrives in Limerick at 09:25. Therefore, the latest time he can get the bus from Oranmore is 07:28.

Step 2

How long does his bus journey take, from Oranmore to Limerick?

99%

104 rated

Answer

The bus leaves Oranmore at 07:28 and arrives in Limerick at 09:25. To find the duration:

  • Calculate the time difference:

    09:25 - 07:28 = 1 hour 57 minutes.

Thus, the journey takes 1 hour and 57 minutes.

Step 3

What fraction of an hour is 15 minutes?

96%

101 rated

Answer

To find the fraction of an hour that 15 minutes represents, note that there are 60 minutes in an hour. Therefore,:

1560=14\frac{15}{60} = \frac{1}{4}

Thus, the answer is ( \frac{1}{4} ).

Step 4

Work out Gina's average speed for the journey, in km/hour.

98%

120 rated

Answer

Gina drives a distance of 90 km in 1 hour and 15 minutes. Convert 1 hour and 15 minutes to hours: 1 hour + ( \frac{15}{60} ) hours = 1.25 hours.

Average speed is calculated as:

Speed=distancetime=90 km1.25 hours=72 km/hourSpeed = \frac{distance}{time} = \frac{90 \text{ km}}{1.25 \text{ hours}} = 72 \text{ km/hour}

Therefore, Gina's average speed for the journey is 72 km/hour.

Join the Junior Cycle students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;