Poppy and Ella ran a 5 km race - Junior Cycle Mathematics - Question 8 - 2019
Question 8
Poppy and Ella ran a 5 km race. The table below shows the total time that it took Poppy and Ella to run each of the given distances in the race. It took Ella 26 minu... show full transcript
Worked Solution & Example Answer:Poppy and Ella ran a 5 km race - Junior Cycle Mathematics - Question 8 - 2019
Step 1
Using the graph, fill in the three missing values for Ella in the table above.
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Answer
The missing values for Ella in the table can be derived from the graph. For:
2 km: 10 minutes
3 km: 17 minutes
4 km: 24 minutes
Therefore, the completed table for Ella is:
Distance (in km) | Total time taken for Ella (minutes)
--- | ---
1 | 4
2 | 10
3 | 17
4 | 24
5 | 26
Step 2
Using the figures in the table, draw a graph on the diagram below to show the time it took Poppy to run d km during the race.
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Answer
The times for Poppy can be plotted based on the values:
Distance 1 km: 5 minutes
Distance 2 km: 12 minutes (calculated as 10 + 2 minutes for the next km)
Distance 3 km: 20 minutes (17 + 3 minutes for the next km)
Distance 4 km: 24 minutes
Distance 5 km: 30 minutes
The graph should connect these points appropriately, showing a steady increase.
Step 3
Who finished first, Ella or Poppy? Tick (✓) one box only. Give a reason for your answer.
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Answer
Ella (✓)
Reason: Ella completed the race in 26 minutes, whereas Poppy took 30 minutes.
Step 4
Tick (✓) the correct box to show what happened to Ella’s speed after 2 km, which is marked A on the graph. Tick one box only. Justify your answer.
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Ella’s speed decreased (✓)
Justification: The graph shows that after 2 km, the slope of Ella’s time line decreases, indicating that it took her longer to complete each subsequent kilometer.
Step 5
Work out Poppy’s average speed for the race, in km per hour.
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Answer
Poppy’s average speed can be calculated using the formula:
Average Speed = Total Distance / Total Time
Total Distance = 5 km
Total Time = 30 minutes = 0.5 hours
Average Speed = 5 km / 0.5 hours = 10 km/h
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