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Pauline flips a fair coin 3 times, and records the outcomes - Junior Cycle Mathematics - Question 1 - 2014

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Pauline flips a fair coin 3 times, and records the outcomes. She writes H for each head and T for each tail. (i) Complete the table below to show all of the possibl... show full transcript

Worked Solution & Example Answer:Pauline flips a fair coin 3 times, and records the outcomes - Junior Cycle Mathematics - Question 1 - 2014

Step 1

Complete the table below to show all of the possible outcomes.

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Answer

H H H
H H T
H T H
H T T
T H H
T H T
T T H
T T T

Step 2

Find the probability of getting two heads and one tail.

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Answer

To find the probability of getting two heads and one tail, we first note that there are a total of 8 outcomes when a coin is flipped 3 times. The successful outcomes for getting exactly 2 heads and 1 tail are HHT, HTH, and THH. Therefore,

extProbability=Number of successful outcomesTotal outcomes=38 ext{Probability} = \frac{\text{Number of successful outcomes}}{\text{Total outcomes}} = \frac{3}{8}.

Step 3

Jamie says: “You have the same probability of getting three heads as you do of getting two heads and one tail.” Do you agree with Jamie? Give a reason for your answer.

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Answer

No, I do not agree with Jamie. The probability of getting three heads (HHH) is

extPr(3H)=18 ext{Pr}(3H) = \frac{1}{8}

while the probability of getting two heads and one tail is

extPr(2H,1T)=38 ext{Pr}(2H, 1T) = \frac{3}{8}.

Step 4

Max says: “You have the same probability of getting H H H as you do of getting H T H.” Do you agree with Max? Give a reason for your answer.

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Answer

Yes, I agree with Max. The probabilities of both events are equal.

  • For HHH: extPr(HHH)=18 ext{Pr}(H H H) = \frac{1}{8}

  • For HTH: extPr(HTH)=18 ext{Pr}(H T H) = \frac{1}{8}

There is only one way to get each event.

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