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Parents Pricing Home Junior Cycle Mathematics Statistics & Data There are 15 boxers in a boxing club
There are 15 boxers in a boxing club - Junior Cycle Mathematics - Question 5 - 2018 Question 5
View full question There are 15 boxers in a boxing club. The weight of each boxer (in kg) is shown in the table below.
| Weight (kg) |
|-------------|
| 47 |
| 49 |
... show full transcript
View marking scheme Worked Solution & Example Answer:There are 15 boxers in a boxing club - Junior Cycle Mathematics - Question 5 - 2018
Complete the stem and leaf diagram below to show this data. Only available for registered users.
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The stem and leaf diagram is completed as follows:
Stem | Leaf
-----|-------
4 | 7 9
5 | 0 6 7 8
6 | 5 7
7 | 5 9
This shows the distribution of weights while following the provided key.
Find the median weight of the boxers. Only available for registered users.
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To calculate the median weight:
List the weights in order:
47, 49, 50, 56, 57, 58, 65, 67, 68, 69, 69, 75, 79
Since there are 15 entries, the median is the 8th entry:
Median = 67 kg.
Find the range of the boxers’ weights. Only available for registered users.
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The range is calculated by finding the difference between the maximum and minimum weights:
Range = Maximum weight - Minimum weight = 79 kg - 47 kg = 32 kg.
Work out the mean weight of the 15 boxers. Only available for registered users.
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To find the mean weight:
Mean = ( \frac{\text{Sum of weights}}{\text{Number of boxers}} = \frac{927 kg}{15} = 61.8 kg ) or approximately 62 kg.
Find the new mean weight of the boxers. Only available for registered users.
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After each boxer loses 1 kg, the new sum of weights becomes:
New sum = 927 kg - 15 kg = 912 kg.
Now, the new mean is:
Mean = ( \frac{912 kg}{15} = 60.8 kg ) or approximately 61 kg.
Work out the new sum of the boxers’ weights. Only available for registered users.
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The new sum of the boxers’ weights after each boxer loses 1 kg is:
New sum = 927 kg - 15 kg = 912 kg.
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