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A circular table is shown in the diagram below - Junior Cycle Mathematics - Question 13 - 2014

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Question 13

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A circular table is shown in the diagram below. Aoife is trying to find the centre of the table. She constructs the right-angled triangle PQR as shown, with |QR| = 1... show full transcript

Worked Solution & Example Answer:A circular table is shown in the diagram below - Junior Cycle Mathematics - Question 13 - 2014

Step 1

Explain why Aoife is correct.

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Answer

Since |∠PQR| = 90°, this indicates that [PR] is a diameter of the circular table. According to the properties of circles, the center of a circle lies on any diameter. Therefore, the center of the circular table must be along the line segment [PR].

Step 2

Use the Theorem of Pythagoras to calculate the length |PR|.

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Answer

Using the Pythagorean theorem:

PR2=PQ2+QR2|PR|^2 = |PQ|^2 + |QR|^2

Substituting the known values:

PR2=(0.75)2+(1)2=0.5625+1=1.5625|PR|^2 = (0.75)^2 + (1)^2 = 0.5625 + 1 = 1.5625

Therefore,

PR=oot1.5625=1.25extm=125extcm.|PR| = oot{1.5625} = 1.25 ext{ m} = 125 ext{ cm}.

Step 3

Find the radius of the table.

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Answer

The diameter of the table, |PR|, is 125 cm. The radius is half the diameter, so:

ext{Radius} = rac{|PR|}{2} = rac{125}{2} = 62.5 ext{ cm}.

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