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In the right-angled triangle shown in the diagram, one of the acute angles is four times as large as the other acute angle - Junior Cycle Mathematics - Question 17 - 2014

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Question 17

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In the right-angled triangle shown in the diagram, one of the acute angles is four times as large as the other acute angle. (i) Find the measures of the two acute a... show full transcript

Worked Solution & Example Answer:In the right-angled triangle shown in the diagram, one of the acute angles is four times as large as the other acute angle - Junior Cycle Mathematics - Question 17 - 2014

Step 1

Find the measures of the two acute angles in the triangle.

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Answer

Let the smallest angle be denoted as xx. Then, the other acute angle is 4x4x. Since the sum of the angles in a triangle is 180ext°180^{ ext{°}}, we have:

extSumofangles=x+4x+90ext°=180ext° ext{Sum of angles} = x + 4x + 90^{ ext{°}} = 180^{ ext{°}}

Simplifying this gives:

5x+90=1805x + 90 = 180

Subtracting 9090 from both sides:

5x=905x = 90

Dividing by 55 yields:

x=18ext°x = 18^{ ext{°}}

Thus, the other acute angle is:

4x=4×18=72ext°4x = 4 \times 18 = 72^{ ext{°}}

Therefore, the two acute angles are 18ext°18^{ ext{°}} and 72ext°72^{ ext{°}}.

Step 2

Find the slope of the line l that contains the hypotenuse of the triangle.

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Answer

In order to find the slope of the line ll that represents the hypotenuse of the triangle, we need to use the angle we found in part (i). The angle of the line with respect to the base is 18ext°18^{ ext{°}}. The slope (mm) is given by:

m=an(heta)m = an( heta)

where heta heta is the angle with the horizontal. Thus:

m=an(18ext°)m0.325m = an(18^{ ext{°}}) \\ m \approx 0.325

So, the slope of the line ll is approximately 0.3250.325, correct to three decimal places.

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