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A solid cone has a radius of 5 cm and a vertical height of 12 cm, as shown - Junior Cycle Mathematics - Question 3 - 2018

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A solid cone has a radius of 5 cm and a vertical height of 12 cm, as shown. (a) Use the theorem of Pythagoras to work out the value of l, the slant height of the co... show full transcript

Worked Solution & Example Answer:A solid cone has a radius of 5 cm and a vertical height of 12 cm, as shown - Junior Cycle Mathematics - Question 3 - 2018

Step 1

Use the theorem of Pythagoras to work out the value of l

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Answer

To find the slant height, l, of the cone, we apply the Pythagorean theorem:

l2=r2+h2l^2 = r^2 + h^2

where:

  • r=5 cmr = 5 \text{ cm} (radius)
  • h=12 cmh = 12 \text{ cm} (height)

Substituting the values:

l2=52+122l^2 = 5^2 + 12^2 l2=25+144l^2 = 25 + 144 l2=169l^2 = 169

Taking the square root:

l=169=13 cml = \sqrt{169} = 13 \text{ cm}

Step 2

Work out the total surface area of the cone

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Answer

The total surface area (TSA) of a cone is given by:

TSA=πrl+πr2TSA = \pi r l + \pi r^2

Substituting the values we found:

  • r=5 cmr = 5 \text{ cm}
  • l=13 cml = 13 \text{ cm}

Calculating each part:

  1. Curved surface area: πrl=π(5)(13)=65π cm2\pi r l = \pi (5)(13) = 65\pi \text{ cm}^2

  2. Base area: πr2=π(5)2=25π cm2\pi r^2 = \pi (5)^2 = 25\pi \text{ cm}^2

Now adding both areas:

TSA=65π+25π=90π282.7 cm2TSA = 65\pi + 25\pi = 90\pi \approx 282.7 \text{ cm}^2

Rounded to one decimal place: TSA ≈ 282.7 cm².

Step 3

Radius of the circle

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Answer

Radius of circle = 5 cm

Step 4

Circumference =

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Answer

Circumference = 2π(5)31.4 cm2\pi(5) \approx 31.4 \text{ cm}

Step 5

Radius of sector =

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Answer

Radius of Sector = 13 cm

Step 6

Length of the arc =

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Answer

Length of Arc = 31.4 cm

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