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A triangle has one side of length 10 cm and another side of length x cm - Junior Cycle Mathematics - Question 11 - 2019

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A triangle has one side of length 10 cm and another side of length x cm. The perimeter of this triangle is 26 cm. The two diagrams below show different possible val... show full transcript

Worked Solution & Example Answer:A triangle has one side of length 10 cm and another side of length x cm - Junior Cycle Mathematics - Question 11 - 2019

Step 1

a) Fill in the length of the third side in each case.

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Answer

For Diagram A:

The perimeter is given by the equation:

a = 10 + x + ext{third side} = 26

Substituting in for x = 5 cm:

a = 10 + 5 + ext{third side} = 26

This simplifies to:

ext{third side} = 26 - 15 = 11 	ext{ cm}.

For Diagram B:

Substituting in for x = 9 cm:

a = 10 + 9 + ext{third side} = 26

This simplifies to:

ext{third side} = 26 - 19 = 7 	ext{ cm}.

Step 2

b) What type of triangle is shown in Diagram A? Give a reason.

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Answer

The triangle in Diagram A is a scalene triangle.

Reason: All sides are different lengths (10 cm, 5 cm, and 11 cm).

Step 3

c)(i) Draw the axis of symmetry of the graph.

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Answer

The axis of symmetry is a vertical line running through the vertex of the parabola, positioned at x = 6. The line can be drawn as a dashed line from the top of the graph down to the x-axis.

Step 4

c)(ii) Use the point A to estimate the area of the triangle in Diagram A.

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Answer

To estimate the area of the triangle in Diagram A using point A on the graph, find the corresponding y-value at x = 5. According to the graph, this area is approximately 25 cm².

Step 5

c)(iii) Plot the point B on the graph.

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At x = 9 cm, the area of the triangle in Diagram B can be found on the graph. The estimated area can be noted and point B should be plotted at this coordinate.

Step 6

d) Construct this triangle in the space below.

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Answer

To construct the triangle, start by drawing a segment of 10 cm. From either endpoint, use a compass to draw arcs of 8 cm from each endpoint, creating intersections. Connect the intersection points to form the triangle and label the sides accordingly.

Step 7

e) Use the theorem of Pythagoras to find the value of h.

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Answer

Using the theorem of Pythagoras, we have:

h2+52=82h^2 + 5^2 = 8^2
h2+25=64h^2 + 25 = 64 h2=39h^2 = 39
h=extsqrt(39)6.2extcmh = ext{sqrt}(39) \approx 6.2 ext{ cm} Therefore, the height h is approximately 6.2 cm, correct to one decimal place.

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