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A uniform metre stick, suspended at its mid-point is balanced as shown - Junior Cycle Science - Question g - 2010

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Question g

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A uniform metre stick, suspended at its mid-point is balanced as shown. Calculate force X. Calculate _______________________________________

Worked Solution & Example Answer:A uniform metre stick, suspended at its mid-point is balanced as shown - Junior Cycle Science - Question g - 2010

Step 1

Calculate 30 cm × X = 3 N × 40 cm

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Answer

To find the value of force X, we set up the equation based on the principle of moments. The sum of moments about the pivot (mid-point of the stick) must be equal.

Using the given distances and forces:

30extcmimesX=3extNimes40extcm30 ext{ cm} imes X = 3 ext{ N} imes 40 ext{ cm}

This equation states that the clockwise moment (due to the 3 N force) equals the counterclockwise moment (due to force X).

Step 2

X = 4

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Answer

Now we can solve for X:

  1. Calculate the right side: 3extNimes40extcm=120extNcm3 ext{ N} imes 40 ext{ cm} = 120 ext{ N cm}

  2. Substitute into the equation: 30extcmimesX=120extNcm30 ext{ cm} imes X = 120 ext{ N cm}

  3. Rearranging gives us: X=120extNcm30extcm=4extNX = \frac{120 ext{ N cm}}{30 ext{ cm}} = 4 ext{ N}

Thus, the value of force X is 4 N.

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