A pupil heated some lauric acid, which is a solid at room temperature, until it turned into a liquid - Junior Cycle Science - Question a - 2008
Question a
A pupil heated some lauric acid, which is a solid at room temperature, until it turned into a liquid. The lauric acid was then allowed to cool at a uniform rate. The... show full transcript
Worked Solution & Example Answer:A pupil heated some lauric acid, which is a solid at room temperature, until it turned into a liquid - Junior Cycle Science - Question a - 2008
Step 1
Draw a graph
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Answer
To draw the graph, plot the temperature on the y-axis and time on the x-axis. Here are the steps:
Plot the following points based on the given data: (0, 75), (1, 64), (2, 54), (3, 43), (4, 43), (5, 43), (6, 32), (7, 22), (8, 10).
Ensure that six points are plotted correctly on the grid.
Connect the points with a smooth curve, showing the decrease in temperature over time.
Step 2
Explain the shape of the graph
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Answer
The shape of the graph features a descending curve with a flat section that indicates a phase change. Initially, the temperature decreases steadily as the lauric acid cools down. When it reaches approximately 43 °C, it remains constant, which signifies the melting point where the solid transitions to a liquid. After this phase, the temperature decreases again until it reaches 10 °C.
Step 3
Use the graph to estimate the melting point of lauric acid
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Answer
From the graph, the melting point of lauric acid can be estimated to be around 43 °C, with a possible variation of ±1 °C.
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