A uniform ladder, of weight 210 N, rests on rough horizontal ground and leans against a smooth vertical wall - Leaving Cert Applied Maths - Question 7 - 2017
Question 7
A uniform ladder, of weight 210 N, rests on rough horizontal ground and leans against a smooth vertical wall.
The foot of the ladder is 2 m from the wall and the to... show full transcript
Worked Solution & Example Answer:A uniform ladder, of weight 210 N, rests on rough horizontal ground and leans against a smooth vertical wall - Leaving Cert Applied Maths - Question 7 - 2017
Step 1
Find the coefficient of friction between the ladder and the ground.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the coefficient of friction (μ) between the ladder and the ground, we start by analyzing the forces acting on the ladder.
Step 1: Analyze Forces
The forces acting on the ladder include:
Weight of the ladder (W) = 210 N acting downward at the center of gravity (midpoint).
Normal reaction (R) from the ground acting upward.
Frictional force (S) acting horizontally at the base in the opposite direction to potential slipping.
Step 2: Set up Equilibrium Equations
Since the ladder is in equilibrium:
The sum of vertical forces must equal zero:
R−W=0⇒R=W=210N
The moment about the base (point where ladder meets ground) must also be zero. We can use the distances to write the moment equation:
S×7=W×1⇒S×7=210×1⇒S=7210=30N
Step 3: Identify the Coefficient of Friction
Using the relation for friction:
μS=R⇒μ=SR=21030=71
Thus, the coefficient of friction is μ=71.
Step 2
Show on a diagram the forces acting on the particle.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The diagram should include the following:
A downward force representing the weight of the particle, marked as 123 N.
Two tension forces (T and S) acting at angles to the horizontal, connecting to the points on the ceiling.
Indicate the angles of the strings with the horizontal as α and β respectively.
Step 3
Write down the two equations that arise from resolving these forces horizontally and vertically.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
For the particle in equilibrium, the forces can be resolved as follows:
Horizontal Forces Equation:
Tcos(α)=Scos(β)
Vertical Forces Equation:
$$ T \sin(\alpha) + S \sin(\beta) = 123 $.
Step 4
Solve these equations to find the tension in each of the strings.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
We use the equations established earlier:
Step 1: Substitute for S
From the horizontal forces equation, we can express S in terms of T:
S=Tcos(β)cos(α)
Substituting this into the vertical forces equation gives:
Tsin(α)+(Tcos(β)cos(α))sin(β)=123
Step 2: Solve for T
Now simplify and isolate T:
After some rearrangement, we will find T=27N.
Step 3: Find S
Substituting the value of T back into either equation will yield:
S=120N
Join the Leaving Cert students using SimpleStudy...