Define (i) acid, (ii) base, according to the theory of Arrhenius, who is pictured on the right - Leaving Cert Chemistry - Question 7 - 2013
Question 7
Define (i) acid, (ii) base, according to the theory of Arrhenius, who is pictured on the right.
Explain the term neutralisation.
Give the name and formula of the str... show full transcript
Worked Solution & Example Answer:Define (i) acid, (ii) base, according to the theory of Arrhenius, who is pictured on the right - Leaving Cert Chemistry - Question 7 - 2013
Step 1
Define (i) acid
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Answer
An acid, according to the theory of Arrhenius, is a substance that dissociates in aqueous solution to give hydrogen ions (H⁺).
Step 2
Define (ii) base
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A base is a substance that dissociates in aqueous solution to produce hydroxide ions (OH⁻).
Step 3
Explain the term neutralisation
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Neutralisation is the chemical reaction between an acid and a base to produce salt and water.
Step 4
Give the name and formula of the strong acid
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The strong acid that is a constituent of gastric juice is hydrochloric acid, represented by the formula HCl.
Step 5
Describe how you would measure the concentration (i) of suspended solids
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To measure the concentration of suspended solids, first find the mass of a pre-weighed filter paper. Then, filter a known volume of water through the filter paper and allow it to dry. After drying, reweigh the filter paper to get the mass of the solids retained. Subtract the initial mass of the filter paper from this mass to obtain the weight of the suspended solids.
Step 6
Describe how you would measure the concentration (ii) of dissolved solids
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To measure the concentration of dissolved solids, find the mass of a clean evaporating dish. After adding a known volume of filtered water to the dish, evaporate the water completely. Once dry, cool the dish and reweigh it. Subtract the initial weight of the dish from the new weight to obtain the mass of the dissolved solids.
Step 7
Express (i) in grams per litre
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To express 0.015 g of suspended solids in a 100 cm³ sample in grams per litre, use the conversion:
