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Define a base according to (i) the Arrhenius theory, (ii) the Brønsted-Lowry theory - Leaving Cert Chemistry - Question b - 2013

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Define a base according to (i) the Arrhenius theory, (ii) the Brønsted-Lowry theory. Give (i) the conjugate acid, (ii) the conjugate base, of HPO₄²⁻. Ammonium hydr... show full transcript

Worked Solution & Example Answer:Define a base according to (i) the Arrhenius theory, (ii) the Brønsted-Lowry theory - Leaving Cert Chemistry - Question b - 2013

Step 1

Define a base according to (i) the Arrhenius theory

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Answer

According to the Arrhenius theory, a base is a substance that dissociates in aqueous solution to produce hydroxyl ions (OH⁻).

Step 2

Define a base according to (ii) the Brønsted-Lowry theory

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Answer

According to the Brønsted-Lowry theory, a base is a proton (H⁺) acceptor, meaning it can accept hydrogen ions in a chemical reaction.

Step 3

Give (i) the conjugate acid of HPO₄²⁻

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Answer

The conjugate acid of HPO₄²⁻ is H₂PO₄⁻.

Step 4

Give (ii) the conjugate base of HPO₄²⁻

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Answer

The conjugate base of HPO₄²⁻ is PO₄³⁻.

Step 5

Calculate the pH of an ammonium hydroxide solution

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Answer

First, calculate the concentration of NH₄OH in mol/L: moles of NH₄OH=7.0 g35 g/mol=0.2 mol.\text{moles of NH₄OH} = \frac{7.0 \text{ g}}{35 \text{ g/mol}} = 0.2 \text{ mol.}

Thus, the concentration is 0.2 M.

Next, calculate the hydroxide ion concentration:

  • For NH₄OH, the base dissociation constant is given, therefore: Kb=[OH]2/[NH4+]K_b = [OH^-]^2 / [NH₄^+]

Calculate [OH⁻]: [OH]=Kb×[NH4OH]initial=(1.8×105)×0.2=1.9×103 M.[OH^-] = \sqrt{K_b \times [NH₄OH]_{initial}} = \sqrt{(1.8 \times 10^{-5}) \times 0.2} = 1.9 \times 10^{-3} \text{ M}.

Then, calculate pOH: pOH=log(1.9×103)=2.72.pOH = - \log(1.9 \times 10^{-3}) = 2.72.

Finally, calculate pH using the relationship: pH=14pOH=142.72=11.28.pH = 14 - pOH = 14 - 2.72 = 11.28.

Thus, the pH of the solution is approximately 11.28.

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