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In the electrolysis of aqueous KI with inert electrodes one half-equation is: $$2I^-(aq) \rightarrow I_2(aq) + 2e^-$$ Write a balanced half-equation for the reaction that takes place at the negative electrode during this electrolysis. - Leaving Cert Chemistry - Question i - 2019
Question i
In the electrolysis of aqueous KI with inert electrodes one half-equation is: $$2I^-(aq) \rightarrow I_2(aq) + 2e^-$$ Write a balanced half-equation for the reacti... show full transcript
Worked Solution & Example Answer:In the electrolysis of aqueous KI with inert electrodes one half-equation is: $$2I^-(aq) \rightarrow I_2(aq) + 2e^-$$ Write a balanced half-equation for the reaction that takes place at the negative electrode during this electrolysis. - Leaving Cert Chemistry - Question i - 2019
Step 1
Write a balanced half-equation for the reaction at the negative electrode
Answer
At the negative electrode (cathode), the reduction of water takes place. The balanced half-equation can be expressed as follows:
In this reaction, water (H₂O) is reduced to hydrogen gas (H₂) and hydroxide ions (OH⁻). The electrons (e⁻) are consumed in the process of reduction.