A reaction vessel of negligible heat capacity held 75 cm³ of 1.0 M HCl solution at a temperature of 13.0 °C - Leaving Cert Chemistry - Question 3 - 2013
Question 3
A reaction vessel of negligible heat capacity held 75 cm³ of 1.0 M HCl solution at a temperature of 13.0 °C. A thermometer was placed in the liquid in the reaction v... show full transcript
Worked Solution & Example Answer:A reaction vessel of negligible heat capacity held 75 cm³ of 1.0 M HCl solution at a temperature of 13.0 °C - Leaving Cert Chemistry - Question 3 - 2013
Step 1
Define heat of reaction.
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Answer
The heat of reaction is defined as the heat change that occurs when the number of moles of reactants in a balanced equation react completely. It is quantified as the heat change for the reaction according to the balanced equation.
Step 2
Suggest a suitable material for the reaction vessel to avoid heat loss to the surroundings.
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Polystyrene or other suitable insulating materials such as plastic or cardboard should be used as they minimize heat transfer to the environment.
Step 3
State (i) one advantage, (ii) one disadvantage, of the use of a burette instead of a graduated cylinder for measuring out the base and adding it to the reaction vessel.
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(i) One advantage of using a burette is that it allows for more precise delivery of the reactant, enabling more accurate measurements.
(ii) One disadvantage is that a burette may be more difficult to read accurately compared to a graduated cylinder, particularly if the level of the liquid is very close to a graduation line.
Step 4
State two ways of ensuring that the rise in temperature was measured as accurately as possible.
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Use a sensitive thermometer that can read to at least 0.2 °C, ensuring it is properly calibrated.
Minimize external influences by covering the reaction vessel to prevent heat loss and ensuring the thermometer is not exposed to air drafts during measurements.
Step 5
How many moles of HCl were neutralized in the reaction with NaOH?
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To calculate the moles of HCl, we can use the formula:
n=CimesV
Where:
C = concentration in mol/L = 1.0 M
V = volume in L = 0.075 L (75 cm³ converted to liters)
Hence,
n=1.0imes0.075=0.075extmol
Step 6
Calculate the heat produced in the reaction vessel as a result of the reaction of the HCl with the NaOH.
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Using the formula for heat transfer:
q=mcheta
Where:
m = mass of the solution = 75 g (since the density of solution is 1 g/cm³)
c = specific heat capacity = 4.2 J/g°C
heta = change in temperature = 20.9 °C - 13.0 °C = 7.9 °C
Hence,
q=75imes4.2imes7.9=2,478.75extJ=2.48extkJ
Step 7
Hence calculate the heat of reaction for the neutralisation reaction between hydrochloric acid and sodium hydroxide.
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To calculate the heat of reaction per mole of HCl:
Identify the hazards associated with the use of hydrochloric acid and sodium hydroxide.
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Hydrochloric acid is corrosive and can cause burns to the skin and eyes. Sodium hydroxide is also corrosive and can cause severe damage to skin and eyes upon contact.
Step 9
Describe how the experiment should be carried out to label the two solutions. What experimental problem would have been encountered if 0.1 M NaOH and 0.1 M HCl solutions had been used instead of 1.0 M solutions?
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To label the two solutions, proper labeling should be done before the experiment includes the correct concentration, compound name, and hazard symbols. If 0.1 M solutions were used, the problem would be that the reaction would be slower and may not reach measurable heat changes, leading to inaccurate results.
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