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The octane number of a fuel is described as a measure of the tendency of the fuel to cause knocking, or as a measure of the tendency of the fuel to resist auto-ignition - Leaving Cert Chemistry - Question 6 - 2005

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The octane number of a fuel is described as a measure of the tendency of the fuel to cause knocking, or as a measure of the tendency of the fuel to resist auto-ignit... show full transcript

Worked Solution & Example Answer:The octane number of a fuel is described as a measure of the tendency of the fuel to cause knocking, or as a measure of the tendency of the fuel to resist auto-ignition - Leaving Cert Chemistry - Question 6 - 2005

Step 1

Name both of the reference hydrocarbons present in the mixture used when measuring octane number by this comparison method.

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Answer

The reference hydrocarbons used in measuring octane number are 2,2,4-trimethylpentane (isoctane) and n-heptane.

Step 2

State two structural features of a hydrocarbon molecule which contribute to it having a high octane number.

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Answer

  1. Short chain length: Hydrocarbons with shorter chains tend to have higher octane numbers due to lower volatility and reduced tendency to knock.

  2. Branching: The presence of branching in hydrocarbons increases the octane number, as branched molecules are more stable during combustion.

Step 3

Why are lead compounds unsuitable as additives for fuel used in modern cars?

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Answer

Lead compounds are unsuitable because they act as catalyst poisons and can damage the catalytic converter in modern vehicles, leading to increased emissions and harmful environmental effects.

Step 4

Identify one additive or type of additive, other than a compound of lead, used to increase the octane number of fuels.

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Answer

Common additives include oxygenates such as ethanol or methanol, which help to enhance the octane rating of fuels.

Step 5

In the case of each of these isomers, draw the structure of the molecule and give its systematic IUPAC name.

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Answer

  1. Pentane: CH3-CH2-CH2-CH2-CH3 (Pentane)

  2. 2-methylbutane: (CH3)2CH-CH2-CH3 (2-methylbutane)

  3. 2,2-dimethylpropane: (CH3)3C-CH3 (2,2-dimethylpropane)

Step 6

Calculate the heat of combustion of liquid benzene.

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Answer

Using the heat of formation data:

We have:

  • For 2C6H6: 2imes49extkJ/mol=98extkJ/mol2 imes 49 ext{ kJ/mol} = 98 ext{ kJ/mol}
  • For 12CO2: 12imes394extkJ/mol=4728extkJ/mol12 imes -394 ext{ kJ/mol} = -4728 ext{ kJ/mol}
  • For 6H2O: 6imes286extkJ/mol=1716extkJ/mol6 imes -286 ext{ kJ/mol} = -1716 ext{ kJ/mol}

The enthalpy change is:

ΔH=ΔHf(products)ΔHf(reactants)\Delta H = \sum{\Delta H_f (products)} - \sum{\Delta H_f (reactants)}

Calculating: ΔH=(47281716)98=3271 kJ/mol\Delta H = (-4728 - 1716) - 98 = -3271 \text{ kJ/mol}

Thus, the heat of combustion of liquid benzene is -3271 kJ/mol.

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