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Name the oil refining process shown in the diagram - Leaving Cert Chemistry - Question 6 - 2016

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Name the oil refining process shown in the diagram. Naphtha is a mixture of hydrocarbons of similar relative molecular masses. Identify the physical property that is... show full transcript

Worked Solution & Example Answer:Name the oil refining process shown in the diagram - Leaving Cert Chemistry - Question 6 - 2016

Step 1

Name the oil refining process shown in the diagram.

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Answer

The oil refining process shown in the diagram is called fractionation or fractional distillation.

Step 2

Identify the physical property that is the basis for these hydrocarbons being isolated as naphtha in this process.

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Answer

The physical property that allows hydrocarbons to be isolated as naphtha in this process is the boiling (condensing) point (temperature).

Step 3

Give a major use for kerosene.

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Answer

A major use for kerosene is as aviation (airplane, jet) fuel.

Step 4

Give a major use for residue.

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Answer

A major use for residue is in roofing, road making, or waterproofing.

Step 5

Name the oil refining process that converts octane into 2,2,4-trimethylpentane.

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Answer

The oil refining process that converts octane into 2,2,4-trimethylpentane is called isomerisation.

Step 6

Name the oil refining process that converts octane into ethylene according to the following balanced equation.

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Answer

The oil refining process that converts octane into ethylene is called dehydrocyclisation/reforming.

Step 7

Explain why these conversions are desirable.

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Answer

These conversions are desirable because they improve octane rating (number), which reduces the tendency of fuels to cause knocking. This is achieved by producing shorter chained hydrocarbons, which are more branched and therefore more efficient.

Step 8

Calculate the heat of reaction for the conversion of octane to ethylene above.

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Answer

To calculate the heat of reaction, we apply Hess's Law. We can calculate it using the equation:

ΔHreaction=ΣΔHf(products)ΣΔHf(reactants)\Delta H_{reaction} = \Sigma \Delta H_{f} (products) - \Sigma \Delta H_{f} (reactants)

Given that:

  • For C₈H₁₈, ( \Delta H_f = -250.1 \text{ kJ mol}^{-1} )
  • For C₈H₄, ( \Delta H_f = -12.5 \text{ kJ mol}^{-1} )

We have:

ΔHreaction=(12.5)(250.1)=237.6 kJ\Delta H_{reaction} = (-12.5) - (-250.1) = 237.6 \text{ kJ}

Step 9

Deduce the molecular formula of the third molecule formed.

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Answer

Since the two known hydrocarbons are octane (C₈H₁₈) and propane (C₃H₈), we can find the molecular formula of the third molecule (C₁₈H₃₈ - C₈H₁₈ - C₃H₈) which results in:

C18H38C8H18C3H8=C7H12C_{18}H_{38} - C_{8}H_{18} - C_{3}H_{8} = C_{7}H_{12}

Thus, the molecular formula of the third molecule is C₇H₁₂.

Step 10

Draw the molecular structure of (i) octane.

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Answer

The molecular structure of octane (C₈H₁₈) is:

       H   H   H   H   H   H   H
       |   |   |   |   |   |   |
  H - C - C - C - C - C - C - C - C - H
       |   |   |   |   |   |   |
       H   H   H   H   H   H   H

Octane has a straight-chain structure.

Step 11

Draw the molecular structure of (ii) 2,2,4-trimethylpentane.

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Answer

The molecular structure of 2,2,4-trimethylpentane (C₈H₁₈) is:

       H   H   H
       |   |   |  
  H - C - C - C - H
       |   |   |  
       H   C - C - H
           |   |  
           H   H  
           |  
           H  
           

It has a branched structure.

Step 12

Draw the molecular structure of (iii) ethylbenzene.

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Answer

The molecular structure of ethylbenzene (C₈H₁₀) is:

          H   H
          |   |
      H - C - C - H
          |     |   
          C - C
          |   |
          H  H  

Ethylbenzene consists of a benzene ring with an ethyl group.

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