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The type of disposable hand warmer shown uses a chemical reaction of iron to generate heat - Leaving Cert Chemistry - Question b - 2016

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The type of disposable hand warmer shown uses a chemical reaction of iron to generate heat. When the outer packaging is removed, oxygen from the air enters the pouch... show full transcript

Worked Solution & Example Answer:The type of disposable hand warmer shown uses a chemical reaction of iron to generate heat - Leaving Cert Chemistry - Question b - 2016

Step 1

What term is used to describe reactions that give out heat energy?

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Answer

The term used to describe reactions that give out heat energy is exothermic.

Step 2

Predict the result you would expect if iron pellets were used instead of the iron powder. Explain your answer.

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Answer

If iron pellets were used instead of iron powder, the result would be that the reaction would take place more slowly. This is because pellets have a smaller surface area compared to the powder. A larger surface area allows for more collisions between reactants, leading to a faster reaction. Therefore, using powder would cause the hand warmer to heat up more quickly than if pellets were used.

Step 3

If a pouch contains 28 g of iron, how many moles of iron are present?

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Answer

To find the number of moles of iron, we can use the formula:

n=mMn = \frac{m}{M}

where:

  • mm is the mass of iron (28 g)
  • MM is the molar mass of iron, which is approximately 56 g/mol

Thus:

n=28extg56extg/mol=0.5extmolesn = \frac{28 ext{ g}}{56 ext{ g/mol}} = 0.5 ext{ moles}

Step 4

How many moles of iron oxide (Fe2O3) are produced when all of the iron in this pouch reacts?

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Answer

From the balanced equation:

4Fe+3O22Fe2O34Fe + 3O_2 \rightarrow 2Fe_2O_3

We can determine the mole ratio:

4extmolesofFe2extmolesofFe2O34 ext{ moles of Fe} \rightarrow 2 ext{ moles of Fe}_2O_3

Thus, if we have 0.5 moles of Fe, we can set up a proportion to find the moles of Fe2O3 produced:

4extmolesFe2extmolesFe2O3=0.5x\frac{4 ext{ moles Fe}}{2 ext{ moles Fe}_2O_3} = \frac{0.5}{x}

Solving for xx gives:

x=0.5imes24=0.25extmolesofFe2O3x = \frac{0.5 imes 2}{4} = 0.25 ext{ moles of Fe}_2O_3

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