The following equation shows the heat of reaction for the formation of benzene:
$$ C_{6}H_{6} + 3H_{2} \rightarrow C_{6}H_{6} $$
$$ \Delta H = +49.1 \text{ kJ mol}^{-1} $$
Is this reaction exothermic or endothermic? Explain your answer. - Leaving Cert Chemistry - Question (d) - 2014
Question (d)
The following equation shows the heat of reaction for the formation of benzene:
$$ C_{6}H_{6} + 3H_{2} \rightarrow C_{6}H_{6} $$
$$ \Delta H = +49.1 \text{ kJ mol}... show full transcript
Worked Solution & Example Answer:The following equation shows the heat of reaction for the formation of benzene:
$$ C_{6}H_{6} + 3H_{2} \rightarrow C_{6}H_{6} $$
$$ \Delta H = +49.1 \text{ kJ mol}^{-1} $$
Is this reaction exothermic or endothermic? Explain your answer. - Leaving Cert Chemistry - Question (d) - 2014
Step 1
Is this reaction exothermic or endothermic?
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Answer
The reaction is endothermic because the change in enthalpy (\Delta H) is positive (+49.1 kJ mol<sup>-1</sup>). A positive value indicates that heat is absorbed during the reaction, meaning that energy is taken in from the surroundings.
Step 2
Explain your answer.
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Answer
In an endothermic reaction, the system absorbs heat, increasing the internal energy of the products compared to the reactants. This can be illustrated by the positive value of \Delta H, which signifies that the heat is not released, but instead is taken in, resulting in an overall energy input into the system.
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