Calculate the number of moles of nitrogen gas at a pressure of 1.85 × 10^6 Pa and a temperature of 293 K in the 6.50 × 10^-3 m³ volume inside a new tennis ball - Leaving Cert Chemistry - Question f - 2015

We can rearrange the equation to solve for $n$:

$n = \frac{PV}{RT}$

Now substitute the values into the equation:

$n = \frac{(1.85 \times 10^6 \text{ Pa})(6.50 \times 10^{-3} \text{ m}^3)}{(8.31 \text{ J/(mol·K)})(293 \text{ K})}$

Calculating this gives:

$n = \frac{(1.85 \times 10^6)(6.50 \times 10^{-3})}{(8.31)(293)} = 0.005 \text{ moles}$

Thus, the number of moles of nitrogen gas is approximately 0.005 moles.