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Write a balanced chemical equation for one of the following reactions from syllabus case studies based on the chemical industry: (i) the synthesis of urea from ammonia; (ii) the combustion of ammonia in air; (iii) the formation of magnesium hydroxide from slaked lime and seawater. - Leaving Cert Chemistry - Question B - 2009

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Write-a-balanced-chemical-equation-for-one-of-the-following-reactions-from-syllabus-case-studies-based-on-the-chemical-industry:--(i)-the-synthesis-of-urea-from-ammonia;--(ii)-the-combustion-of-ammonia-in-air;--(iii)-the-formation-of-magnesium-hydroxide-from-slaked-lime-and-seawater.-Leaving Cert Chemistry-Question B-2009.png

Write a balanced chemical equation for one of the following reactions from syllabus case studies based on the chemical industry: (i) the synthesis of urea from ammo... show full transcript

Worked Solution & Example Answer:Write a balanced chemical equation for one of the following reactions from syllabus case studies based on the chemical industry: (i) the synthesis of urea from ammonia; (ii) the combustion of ammonia in air; (iii) the formation of magnesium hydroxide from slaked lime and seawater. - Leaving Cert Chemistry - Question B - 2009

Step 1

the synthesis of urea from ammonia;

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Answer

The balanced chemical equation for the synthesis of urea from ammonia is:

2NH3+CO2(NH2)2CO+H2O2 \text{NH}_3 + \text{CO}_2 \rightarrow \text{(NH}_2\text{)}_2\text{CO} + \text{H}_2\text{O}

Where:

  • 2 moles of ammonia react with 1 mole of carbon dioxide to produce 1 mole of urea and 1 mole of water.

Step 2

the combustion of ammonia in air;

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Answer

The balanced equation for the combustion of ammonia in air is:

4NH3+3O22N2+6H2O4 \text{NH}_3 + 3 \text{O}_2 \rightarrow 2 \text{N}_2 + 6 \text{H}_2\text{O}

In this reaction, 4 moles of ammonia combust in the presence of 3 moles of oxygen to yield 2 moles of nitrogen and 6 moles of water.

Step 3

the formation of magnesium hydroxide from slaked lime and seawater.

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Answer

The balanced equation for the formation of magnesium hydroxide from slaked lime (calcium hydroxide) and seawater is:

Ca(OH)2+MgCl2Mg(OH)2+CaCl2\text{Ca(OH)}_2 + \text{MgCl}_2 \rightarrow \text{Mg(OH)}_2 + \text{CaCl}_2

In this reaction, calcium hydroxide reacts with magnesium chloride to form magnesium hydroxide and calcium chloride.

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