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Both carbon disulfide (CS2) and tetrachloromethane (CCl4) are colourless liquids at room temperature - Leaving Cert Chemistry - Question 11 - 2018
Question 11
Both carbon disulfide (CS2) and tetrachloromethane (CCl4) are colourless liquids at room temperature. (i) Define electronegativity. (ii) Predict the type of bond f... show full transcript
Worked Solution & Example Answer:Both carbon disulfide (CS2) and tetrachloromethane (CCl4) are colourless liquids at room temperature - Leaving Cert Chemistry - Question 11 - 2018
Step 1
Step 2
Predict the type of bond formed between carbon and chlorine atoms in a CCl4 molecule.
Answer
The bond formed between carbon and chlorine atoms in a CCl4 molecule is a polar covalent bond. This occurs because chlorine is more electronegative than carbon, leading to an unequal sharing of electrons.
Step 3
Step 4
State and account for the shape of a tetrachloromethane molecule.
Answer
The shape of a tetrachloromethane molecule (CCl4) is tetrahedral. This shape arises because there are four bonding pairs of electrons and no lone pairs around the carbon atom, resulting in a symmetrical distribution of bonds.
Step 5
Draw a dot and cross diagram to show the arrangement of all the valence shell electrons in a CS2 molecule.
Answer
The dot and cross diagram for a CS2 molecule shows two sulfur atoms bonded to a central carbon atom. The diagram would illustrate carbon sharing its four valence electrons (represented as dots) with the two sulfur atoms, while sulfur shares its valence electrons (represented as crosses). The correct representation will have each atom surrounded by the appropriate number of shared and lone electrons.