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How many atoms of iron are there in a 30 g bowl of cornflakes that contains 0.0024 g iron per 30 g serving? - Leaving Cert Chemistry - Question d - 2010

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How many atoms of iron are there in a 30 g bowl of cornflakes that contains 0.0024 g iron per 30 g serving?

Worked Solution & Example Answer:How many atoms of iron are there in a 30 g bowl of cornflakes that contains 0.0024 g iron per 30 g serving? - Leaving Cert Chemistry - Question d - 2010

Step 1

Calculate the number of moles of iron

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Answer

To find the number of moles of iron in the bowl of cornflakes, we can use the formula:

n = rac{m}{M}

where:

  • m=0.0024gm = 0.0024 \, g (mass of iron)
  • M=56g/molM = 56 \, g/mol (molar mass of iron)

Using the values:

n = rac{0.0024 \, g}{56 \, g/mol} = 4.29 \times 10^{-5} \, mol

Step 2

Calculate the number of atoms of iron

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Answer

Next, to convert moles of iron to atoms, we use Avogadro's number (NA=6.022×1023atoms/molN_A = 6.022 \times 10^{23} \, atoms/mol):

N=n×NAN = n \times N_A

Substituting the known values:

N=4.29×105mol×6.022×1023atoms/mol=2.6×1019atomsN = 4.29 \times 10^{-5} \, mol \times 6.022 \times 10^{23} \, atoms/mol = 2.6 \times 10^{19} \, atoms

Thus, there are approximately 2.6×10192.6 \times 10^{19} atoms of iron in the 30 g bowl of cornflakes.

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