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7. (a) Define (i) acid, (ii) base, according to the theory of Arrhenius, who is pictured on the right - Leaving Cert Chemistry - Question 7 - 2013

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7. (a) Define (i) acid, (ii) base, according to the theory of Arrhenius, who is pictured on the right. Explain the term neutralisation. Give the name and formula o... show full transcript

Worked Solution & Example Answer:7. (a) Define (i) acid, (ii) base, according to the theory of Arrhenius, who is pictured on the right - Leaving Cert Chemistry - Question 7 - 2013

Step 1

Define (i) acid

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Answer

An acid is defined as a substance that dissociates to give hydrogen ions (H⁺) in aqueous solution.

Step 2

Define (ii) base

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Answer

A base is defined as a substance that dissociates to give hydroxide ions (OH⁻) in aqueous solution.

Step 3

Explain the term neutralisation

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Answer

Neutralisation is the chemical reaction between an acid and a base, resulting in the formation of salt and water. It is characterized by the equation:

ightarrow ext{Salt} + ext{Water}$$

Step 4

Give the name and formula of the strong acid which is a constituent of gastric juice in the stomach

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Answer

The strong acid that is a constituent of gastric juice is hydrochloric acid, with the formula HCl.

Step 5

Describe how you would measure the concentration (i) of suspended solids

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Answer

To measure the concentration of suspended solids, follow these steps:

  1. Find the mass of a dry filter paper using a balance.
  2. Filter a known volume of the water sample through the weighed filter paper.
  3. Dry the filter paper completely.
  4. Reweigh the filter paper to determine the mass after filtering.
  5. Calculate the mass of suspended solids by subtracting the initial weight of the filter paper from the final weight.

Step 6

Describe how you would measure the concentration (ii) of dissolved solids

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Answer

To measure the concentration of dissolved solids, perform the following:

  1. Find the mass of an evaporating dish using a balance.
  2. Evaporate a known volume of the filtered water in the dish until dry.
  3. Allow the dish to cool and then reweigh it.
  4. Calculate the mass of dissolved solids by subtracting the initial weight of the dish from the final weight.

Step 7

Express (i) in grams per litre

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Answer

To express the concentration of suspended solids in grams per litre: 0.015extgextin0.1extL=0.15extg/L0.015 ext{ g} ext{ in } 0.1 ext{ L} = 0.15 ext{ g/L} Thus, the concentration is 0.15 g/L.

Step 8

Express (ii) in parts per million (ppm)

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Answer

To express the concentration in parts per million (ppm): To convert grams to mg, we multiply by 1000:

  • For suspended solids: 0.015extg=15extmg0.015 ext{ g} = 15 ext{ mg}
  • For dissolved solids: 0.17extg=170extmg0.17 ext{ g} = 170 ext{ mg}

Now, using the total volume of the sample: ext{ppm} = rac{ ext{mg of substance}}{ ext{L of solution}} \times 1000

Thus,

  • Concentration of suspended solids in ppm: 15extppm15 ext{ ppm}
  • Concentration of dissolved solids in ppm: 170extppm170 ext{ ppm}

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