7. (a) Define (i) acid, (ii) base, according to the theory of Arrhenius,
who is pictured on the right - Leaving Cert Chemistry - Question 7 - 2013
Question 7
7. (a) Define (i) acid, (ii) base, according to the theory of Arrhenius,
who is pictured on the right.
Explain the term neutralisation.
Give the name and formula o... show full transcript
Worked Solution & Example Answer:7. (a) Define (i) acid, (ii) base, according to the theory of Arrhenius,
who is pictured on the right - Leaving Cert Chemistry - Question 7 - 2013
Step 1
Define (i) acid
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Answer
An acid is defined as a substance that dissociates to give hydrogen ions (H⁺) in aqueous solution.
Step 2
Define (ii) base
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A base is defined as a substance that dissociates to give hydroxide ions (OH⁻) in aqueous solution.
Step 3
Explain the term neutralisation
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Neutralisation is the chemical reaction between an acid and a base, resulting in the formation of salt and water. It is characterized by the equation:
ightarrow ext{Salt} + ext{Water}$$
Step 4
Give the name and formula of the strong acid which is a constituent of gastric juice in the stomach
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The strong acid that is a constituent of gastric juice is hydrochloric acid, with the formula HCl.
Step 5
Describe how you would measure the concentration (i) of suspended solids
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Answer
To measure the concentration of suspended solids, follow these steps:
Find the mass of a dry filter paper using a balance.
Filter a known volume of the water sample through the weighed filter paper.
Dry the filter paper completely.
Reweigh the filter paper to determine the mass after filtering.
Calculate the mass of suspended solids by subtracting the initial weight of the filter paper from the final weight.
Step 6
Describe how you would measure the concentration (ii) of dissolved solids
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To measure the concentration of dissolved solids, perform the following:
Find the mass of an evaporating dish using a balance.
Evaporate a known volume of the filtered water in the dish until dry.
Allow the dish to cool and then reweigh it.
Calculate the mass of dissolved solids by subtracting the initial weight of the dish from the final weight.
Step 7
Express (i) in grams per litre
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Answer
To express the concentration of suspended solids in grams per litre:
0.015extgextin0.1extL=0.15extg/L
Thus, the concentration is 0.15 g/L.
Step 8
Express (ii) in parts per million (ppm)
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To express the concentration in parts per million (ppm):
To convert grams to mg, we multiply by 1000:
For suspended solids:
0.015extg=15extmg
For dissolved solids:
0.17extg=170extmg
Now, using the total volume of the sample:
ext{ppm} = rac{ ext{mg of substance}}{ ext{L of solution}} \times 1000
Thus,
Concentration of suspended solids in ppm: 15extppm
Concentration of dissolved solids in ppm: 170extppm
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