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The given table shows the solidification temperatures for various alloys of metal A and metal B - Leaving Cert Engineering - Question b - 2007

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The given table shows the solidification temperatures for various alloys of metal A and metal B. The melting point of A is 1083°C and B is 1453°C. % of metal B in a... show full transcript

Worked Solution & Example Answer:The given table shows the solidification temperatures for various alloys of metal A and metal B - Leaving Cert Engineering - Question b - 2007

Step 1

Draw the equilibrium diagram according to the given data

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Answer

To draw the equilibrium diagram, plot the solidification temperatures against the percentage of metal B in the alloy.

  1. Start with the temperature on the vertical axis ranging from 1083°C to 1453°C.
  2. On the horizontal axis, plot the percentage of metal B from 0% to 100%.
  3. Mark the start and end of solidification points for each percentage of metal B based on the provided data.
  4. Connect the points for the start of solidification with a solid line (solidus line) and the end of solidification with a dashed line (liquidus line).

Ensure that the lines correctly represent the liquid and solid phases as per the melting temperatures of metals A and B.

Step 2

Label the diagram and describe the main features

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Answer

The equilibrium diagram should include the following labels:

  • Liquid: The area above the liquidus line where the alloy is completely liquid.
  • Liquid + Solid: The region between the liquidus and solidus lines, indicating the alloy is in a pasty state.
  • Solid: The area below the solidus line, where the alloy is completely solid.

Descriptions:

  • Liquidus Line: Indicates the transition from fully liquid to pasty state. Above this line, the alloy is liquid.
  • Solidus Line: Marks the transition from pasty to solid state. Below this line, the alloy is cooling and entirely solid.
  • Both metals A and B are soluble in each other in the liquid state.

Step 3

For the alloy with 50% B determine, from the diagram, the ratio of the phases at 1250°C

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Answer

From the diagram, find the positions corresponding to 50% B at the temperature of 1250°C:

  • Mass of solid (A): 26 units
  • Mass of liquid (C): 66 units

The ratio of phases at 1250°C consists of:

  • Solid: 2650=2426 - 50 = 24
  • Liquid: 6650=1666 - 50 = 16

Thus, the ratio of phases is:

Ratio of solid to liquid=2416=32\text{Ratio of solid to liquid} = \frac{24}{16} = \frac{3}{2}

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