A square sheet of cardboard, of side 10 units, is used to make an open box - Leaving Cert Mathematics - Question 8 - 2021
Question 8
A square sheet of cardboard, of side 10 units, is used to make an open box.
Squares of side x units, where x ∈ ℝ, are removed from each corner of the cardboard and ... show full transcript
Worked Solution & Example Answer:A square sheet of cardboard, of side 10 units, is used to make an open box - Leaving Cert Mathematics - Question 8 - 2021
Step 1
a) The length (l), breadth (b) and height (h) of the box are shown in the diagram above. Write l, b, and h in terms of x.
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Answer
The dimensions of the box can be defined in terms of the variable x:
The length (l) of the box will be equal to the original length of the cardboard minus twice the side of the squares cut out: l=10−2x
The breadth (b) follows the same logic: b=10−2x
The height (h) of the box is simply the side of the squares cut out, which is: h=x
Step 2
b) Show that the volume of the box can be written as V(x) = 4x^3 - 40x^2 + 100x.
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Answer
To find the volume (V) of the box, we can use the formula: V=limesbimesh
Substituting the expressions for l, b, and h from part (a): V=(10−2x)(10−2x)(x)
Expanding this, we first multiply the two expressions: =(10−2x)(10−2x)=100−40x+4x2
Now, multiplying by x: V=x(100−40x+4x2) =100x−40x2+4x3
By rearranging, we can express this as: V(x)=4x3−40x2+100x.
Step 3
c) Explain why a box of height 6 units cannot be made from the sheet of cardboard.
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Answer
To have a box of height 6 units, we need x = 6. Using the formula for the dimensions, we find the width: b=10−2x=10−2(6)=10−12=−2
Since a negative width does not make sense in this context, it is concluded that a height of 6 units cannot be obtained, as it results in a negative dimension for the box.
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