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Two complex numbers are $u = 3 + 2i$ and $v = -1 + i$, where $i^2 = -1$ - Leaving Cert Mathematics - Question 3 - 2014

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Two-complex-numbers-are-$u-=-3-+-2i$-and-$v-=--1-+-i$,-where-$i^2-=--1$-Leaving Cert Mathematics-Question 3-2014.png

Two complex numbers are $u = 3 + 2i$ and $v = -1 + i$, where $i^2 = -1$. (a) Given that $w = u - v - 2$, evaluate $w$. (b) Plot $u$, $v$, and $w$ on the Argand dia... show full transcript

Worked Solution & Example Answer:Two complex numbers are $u = 3 + 2i$ and $v = -1 + i$, where $i^2 = -1$ - Leaving Cert Mathematics - Question 3 - 2014

Step 1

Evaluate $w$

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Answer

To evaluate ww, we substitute the values of uu and vv:

w=(3+2i)(1+i)2 w = (3 + 2i) - (-1 + i) - 2

Now, simplify the expression:

w=(3+2i)+(1i)2 w = (3 + 2i) + (1 - i) - 2 =(3+12)+(2ii) = (3 + 1 - 2) + (2i - i) =2+i. = 2 + i.

Step 2

Plot $u$, $v$, and $w$ on the Argand diagram

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Answer

To plot the complex numbers on the Argand diagram:

  • For u=3+2iu = 3 + 2i, plot the point (3, 2).
  • For v=1+iv = -1 + i, plot the point (-1, 1).
  • For w=2+iw = 2 + i, plot the point (2, 1).

Place these points in their respective locations on the diagram.

Step 3

Find $\frac{2u + v}{w}$

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Answer

First, we simplify the top line:

2u+v=2(3+2i)+(1+i)=6+4i1+i=5+5i. 2u + v = 2(3 + 2i) + (-1 + i) = 6 + 4i - 1 + i = 5 + 5i.

To divide these two complex numbers, we will multiply the fraction top and bottom by the conjugate of the denominator, ww:

2u+vw=5+5i2+i. \frac{2u + v}{w} = \frac{5 + 5i}{2 + i}.

Now, multiplying both the numerator and the denominator by the conjugate of the denominator, 2i2 - i:

(5+5i)(2i)(2+i)(2i)=105i+10i5i24+1. \frac{(5 + 5i)(2 - i)}{(2 + i)(2 - i)} = \frac{10 - 5i + 10i - 5i^2}{4 + 1}.

Recall that i2=1i^2 = -1, so this simplifies to:

10+5+5i5=15+5i5=3+i. \frac{10 + 5 + 5i}{5} = \frac{15 + 5i}{5} = 3 + i.

Thus, we find:

2u+vw=3+i.\frac{2u + v}{w} = 3 + i.

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