Photo AI

(a) (i) Find the number of different arrangements that can be made using all the letters of the word RAINBOW - Leaving Cert Mathematics - Question 3 - 2018

Question icon

Question 3

(a)-(i)-Find-the-number-of-different-arrangements-that-can-be-made-using-all-the-letters-of-the-word-RAINBOW-Leaving Cert Mathematics-Question 3-2018.png

(a) (i) Find the number of different arrangements that can be made using all the letters of the word RAINBOW. Each letter is used only once. (ii) Find the number of... show full transcript

Worked Solution & Example Answer:(a) (i) Find the number of different arrangements that can be made using all the letters of the word RAINBOW - Leaving Cert Mathematics - Question 3 - 2018

Step 1

Find the number of different arrangements that can be made using all the letters of the word RAINBOW.

96%

114 rated

Answer

To find the number of different arrangements of the letters in the word RAINBOW, we need to calculate the factorial of the number of letters. Since RAINBOW consists of 7 distinct letters, the total arrangements can be calculated as:

7!=7imes6imes5imes4imes3imes2imes1=50407! = 7 imes 6 imes 5 imes 4 imes 3 imes 2 imes 1 = 5040

Thus, the number of arrangements is 5040.

Step 2

Find the number of different 3-letter arrangements that can be made using the letters of the word RAINBOW.

99%

104 rated

Answer

For 3-letter arrangements using letters from RAINBOW, we can select any 3 letters from the 7 distinct letters available. The number of arrangements can be calculated using the formula for permutations:

P(n, r) = rac{n!}{(n - r)!}

Here, n = 7 (total letters) and r = 3 (letters to arrange):

P(7, 3) = rac{7!}{(7-3)!} = rac{7!}{4!} = 7 imes 6 imes 5 = 210

Thus, there are 210 different 3-letter arrangements.

Step 3

Complete the “Probability” column of the table which shows the probability of the spinner coming to rest in each sector after one spin.

96%

101 rated

Answer

To find the probability, we need to divide the angle of each sector by the total angle of the spinner, which is 360°:

  • Red: P(R)=72360=15P(R) = \frac{72}{360} = \frac{1}{5}
  • Orange: P(O)=30360=112P(O) = \frac{30}{360} = \frac{1}{12}
  • Yellow: P(Y)=45360=18P(Y) = \frac{45}{360} = \frac{1}{8}
  • Green: P(G)=90360=14P(G) = \frac{90}{360} = \frac{1}{4}
  • Blue: P(B)=60360=16P(B) = \frac{60}{360} = \frac{1}{6}
  • Indigo: P(I)=18360=120P(I) = \frac{18}{360} = \frac{1}{20}
  • Violet: P(V)=45360=18P(V) = \frac{45}{360} = \frac{1}{8}

Including these probabilities in the table yields:

Colour Angle Probability Red 72° 1/5 Orange 30° 1/12 Yellow 45° 1/8 Green 90° 1/4 Blue 60° 1/6 Indigo 18° 1/20 Violet 45° 1/8

Step 4

Find the expected value of the prize that a player wins if they play Rainbow.

98%

120 rated

Answer

The expected value (E) can be calculated as:

E(X)=i=1n(Xi×P(Xi))E(X) = \sum_{i=1}^{n} (X_i \times P(X_i))

Calculating each contribution:

  • For Red: 20×15=4 €20 \times \frac{1}{5} = €4
  • For Orange: 60×112=5 €60 \times \frac{1}{12} = €5
  • For Yellow: 24×18=3 €24 \times \frac{1}{8} = €3
  • For Green: 42×14=10.5 €42 \times \frac{1}{4} = €10.5
  • For Blue: 41×16=6.8333 €41 \times \frac{1}{6} = €6.8333
  • For Indigo: 90×120=4.5 €90 \times \frac{1}{20} = €4.5
  • For Violet: 48×18=6 €48 \times \frac{1}{8} = €6

Summing these values:

E(X)=4+5+3+10.5+6.8333+4.5+6=31.0E(X) = 4 + 5 + 3 + 10.5 + 6.8333 + 4.5 + 6 = 31.0

Thus, the expected value is €31.50.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;