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The graph of a cubic function $p(x)$ is shown in the first diagram below, for $0 \leq x \leq 4$, $x \in \mathbb{R}$ - Leaving Cert Mathematics - Question 6(c) - 2022

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Question 6(c)

The-graph-of-a-cubic-function-$p(x)$-is-shown-in-the-first-diagram-below,-for-$0-\leq-x-\leq-4$,-$x-\in-\mathbb{R}$-Leaving Cert Mathematics-Question 6(c)-2022.png

The graph of a cubic function $p(x)$ is shown in the first diagram below, for $0 \leq x \leq 4$, $x \in \mathbb{R}$. The maximum value of $p'(x)$ in this domain is 1... show full transcript

Worked Solution & Example Answer:The graph of a cubic function $p(x)$ is shown in the first diagram below, for $0 \leq x \leq 4$, $x \in \mathbb{R}$ - Leaving Cert Mathematics - Question 6(c) - 2022

Step 1

Plot the point at $x = 0$

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Answer

The derivative p(0)=3p'(0) = -3, which means we plot the point (0, -3).

Step 2

Plot the point at $x = 1$

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Answer

Given the graph of p(x)p(x), the slope of the tangent at x=1x = 1 indicates that p(1)=0p'(1) = 0. Therefore, we plot the point (1, 0).

Step 3

Plot the point at $x = 2$

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Answer

At x=2x = 2, the graph of p(x)p(x) shows a local maximum; hence, p(2)=1p'(2) = 1. We plot the point (2, 1).

Step 4

Plot the point at $x = 3$

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Answer

At x=3x = 3, the slope of the tangent is also 0, indicating that p(3)=0p'(3) = 0. Thus, we plot the point (3, 0).

Step 5

Plot the point at $x = 4$

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Answer

Finally, at x=4x = 4, the graph of p(x)p(x) indicates that p(4)=3p'(4) = -3. Hence, we plot the point (4, -3).

Step 6

Draw the graph of $p'(x)$

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Answer

Now, connect the plotted points (0, -3), (1, 0), (2, 1), (3, 0), and (4, -3) with a smooth curve, ensuring the correct shape of the cubic function is represented. The graph should reflect the changes in slope as seen in the original cubic function's graph.

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