Put one tick into the table for each statement to indicate whether the statement is Always True, Sometimes True or Never True - Leaving Cert Mathematics - Question b - 2018
Question b
Put one tick into the table for each statement to indicate whether the statement is Always True, Sometimes True or Never True.
In the table, n is the size of the sam... show full transcript
Worked Solution & Example Answer:Put one tick into the table for each statement to indicate whether the statement is Always True, Sometimes True or Never True - Leaving Cert Mathematics - Question b - 2018
Step 1
1. When forming confidence intervals (for fixed n and $ar{p}$), an increased confidence level implies a wider interval.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is Always True. A higher confidence level leads to a wider interval as it requires capturing a larger amount of variability in the population.
Step 2
2. As the value of $ar{p}$ increases (for fixed n), the estimated standard error of the population proportion increases.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is Sometimes True. The standard error is calculated as
SE = rac{ar{p}(1 - ar{p})}{ ext{sqrt}(n)}
which means the standard error is at a maximum when ar{p} = 0.5; thus, it does not necessarily increase with ar{p}.
Step 3
3. As the value of $ar{p}(1 - ar{p})$ increases (for fixed n), the estimated standard error of the population proportion increases.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is Always True. The term ar{p}(1 - ar{p}) directly affects the standard error, thus as it increases, so does the error.
Step 4
4. As n, the number of people sampled, increases (for fixed $ar{p}$), the estimated standard error of the population proportion increases.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
This statement is Never True. As n increases, the standard error decreases because it is inversely proportional to the square root of n.
Step 5
(ii) Using calculus or otherwise, find the maximum value of $ar{p}(1 - ar{p})$.
97%
117 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the maximum value of ar{p}(1 - ar{p}), we can consider the function:
f(ar{p}) = ar{p} - ar{p}^2
Taking the derivative:
f'(ar{p}) = 1 - 2ar{p}
Setting the derivative equal to zero gives:
ightarrow ar{p} = rac{1}{2}$$
Plugging back to find the maximum:
$$M = ar{p}(1 - ar{p}) = rac{1}{2}(1 - rac{1}{2}) = rac{1}{4} = 0.25$$
Step 6
(iii) Hence, find the largest possible value of the radius of the 95% confidence interval for a population proportion, given a random sample of size 800.
97%
121 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Considering the maximum of eigenvalue M processed earlier, the standard error is calculated as:
SE = rac{ar{p}(1 - ar{p})}{ ext{sqrt}(n)}
With ar{p} = rac{1}{2} and n=800:
= rac{0.25}{28.2843} \
ightarrow SE ext{ approximately equals } 0.0088$$
For a 95% confidence interval, we use:
$$z = 1.96$$
Thus, the radius of the confidence interval is:
$$R = z imes SE = 1.96 imes 0.0088 \
ightarrow R ext{ approximately equals } 0.0173 ext{ or } 1.73 ext{%.}$$
Join the Leaving Cert students using SimpleStudy...