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Write each of the following values in the form $\alpha \times 10^n$ where $1 \leq \alpha < 10$ and $n \in \mathbb{Z}$ - Leaving Cert Mathematics - Question 5 - 2022

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Write each of the following values in the form $\alpha \times 10^n$ where $1 \leq \alpha < 10$ and $n \in \mathbb{Z}$. (i) 1200 (ii) 0.27 A falcon can dive at a s... show full transcript

Worked Solution & Example Answer:Write each of the following values in the form $\alpha \times 10^n$ where $1 \leq \alpha < 10$ and $n \in \mathbb{Z}$ - Leaving Cert Mathematics - Question 5 - 2022

Step 1

Write in the form $\alpha \times 10^n$ for 1200

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Answer

To express 1200 in the form α×10n\alpha \times 10^n, we can write it as:

1200=1.2×1031200 = 1.2 \times 10^3

This transformation makes sure that 1α<101 \leq \alpha < 10.

Step 2

Write in the form $\alpha \times 10^n$ for 0.27

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Answer

For the value 0.27, we can write it as:

0.27=2.7×1010.27 = 2.7 \times 10^{-1}

This is within the required range of α\alpha.

Step 3

Use this to work out how long it would take the falcon to travel 100 metres.

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Answer

First, convert the falcon's speed from miles per hour to metres per second:

  1. Speed of the falcon: 120 miles per hour.

    • Convert to kilometres per hour: 120 miles x 1.6 km/mile = 192 km/h.
    • Convert to metres per second: (192 \text{ km/h} = \frac{192000 ext{ m}}{3600 ext{ s}} = 53.33 \text{ m/s}).
  2. Calculate the time to travel 100 metres:

    • Using the formula ( \text{Time} = \frac{\text{Distance}}{\text{Speed}} ): Time for 100 m=100extm53.33 m/s1.875extseconds\text{Time for 100 m} = \frac{100 ext{ m}}{53.33 \text{ m/s}} \approx 1.875 ext{ seconds}
    • So, rounded to one decimal place, the time is approximately 1.9 seconds.

Step 4

the two values of x for which m(x) = 0

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From the graph, we can observe the intersections of the curve m(x)m(x) with the x-axis. The estimated values for ( x ) where ( m(x) = 0 ) are:

x=1 or x=4x = 1\text{ or } x = 4.

Step 5

the range of values of x for which k(x) is less than m(x)

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Answer

By analyzing the graph, we see that k(x)k(x) is less than m(x)m(x) between the intervals from:

2<x<3.52 < x < 3.5

Therefore, for these values, ( k(x) < m(x) ).

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