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(a) The mean distance from the earth to the sun is 149 597 871 km - Leaving Cert Mathematics - Question Question (a) and (b) - 2013

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Question Question (a) and (b)

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(a) The mean distance from the earth to the sun is 149 597 871 km. Write this number in the form $a \times 10^n$, where $1 < a < 10$ and $n \in \mathbb{Z}$, correct ... show full transcript

Worked Solution & Example Answer:(a) The mean distance from the earth to the sun is 149 597 871 km - Leaving Cert Mathematics - Question Question (a) and (b) - 2013

Step 1

Write the mean distance from the Earth to the Sun in scientific notation

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Answer

To convert 149,597,871 km into scientific notation, we first express it as follows:

149597871=1.5×108149597871 = 1.5 \times 10^8

Here, 1.51.5 is between 1 and 10 and 88 is an integer.

Step 2

Write each of the numbers below as a decimal correct to two decimal places

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Answer

VariableCalculationResult
A5\sqrt{5}2.24
B24385\frac{243}{85}2.86
Ctan(70°)\tan(70°)2.75
D3π4\frac{3\pi}{4}2.36
E250100\frac{250}{100}2.50
F(1+110)10\left(1 + \frac{1}{10}\right)^{10}2.59

Step 3

Mark 5 of the numbers in the table on the number line below and label each number clearly

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Answer

On the number line provided, we can mark the following values:

  • 2 at position 2
  • 2.24 at position A
  • 2.50 at position F
  • 2.75 at position E
  • 2.86 at position B

The completed number line would look like this:

<----|----|---A---|---B---|-----|---F---|---2----|---2.5---3--->
     2   2.24  2.86   2.5   2.75

Step 4

Solve the equation $27^{n} = 3^{n + 10}$

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Answer

To solve for nn, we start by rewriting 2727 as 333^3:

27n=(33)n=33n27^{n} = (3^{3})^{n} = 3^{3n}

Now we can equate the exponents: 33n=3n+103^{3n} = 3^{n + 10}

This gives us: 3n=n+103n = n + 10

Subtracting nn from both sides: 2n=102n = 10

Dividing by 2: n=5n = 5

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