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In a large population 1 in 8 of the people play tennis - Leaving Cert Mathematics - Question (b) - 2020

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In a large population 1 in 8 of the people play tennis. (i) Four people are chosen at random from the population. What is the probability that the fourth person cho... show full transcript

Worked Solution & Example Answer:In a large population 1 in 8 of the people play tennis - Leaving Cert Mathematics - Question (b) - 2020

Step 1

Four people are chosen at random from the population. What is the probability that the fourth person chosen is the only one to play tennis?

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Answer

To find the probability that the fourth person is the only one who plays tennis, we need to consider the following:

  1. The probability that the first three people do not play tennis is:

    P(NoTennis)=(1P(Tennis))3=(78)3P(No Tennis) = (1 - P(Tennis))^3 = \left( \frac{7}{8} \right)^3

  2. The probability that the fourth person does play tennis is:

    P(Tennis)=18P(Tennis) = \frac{1}{8}

  3. Therefore, the combined probability can be calculated as follows:

    P(Fourth=Tennis)=(78)3×18P(Fourth = Tennis) = \left( \frac{7}{8} \right)^3 \times \frac{1}{8}

Calculating this gives:

=34340960.08374= \frac{343}{4096} \approx 0.08374

Step 2

Three people are chosen at random from the population. What is the probability that exactly two of them play tennis?

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Answer

To determine the probability that exactly two out of three people play tennis, we can use the binomial probability formula:

  1. The number of ways to choose 2 people from 3 is:

    (32)=3\binom{3}{2} = 3

  2. The probability that 2 people play tennis and 1 does not is:

    P(Exactly2Tennis)=(32)×(P(Tennis))2×(P(NoTennis))1P(Exactly 2 Tennis) = \binom{3}{2} \times (P(Tennis))^2 \times (P(No Tennis))^1

So we have:

  • Probability of tennis = ( P(Tennis) = \frac{1}{8} )
  • Probability of not playing tennis = ( P(No Tennis) = \frac{7}{8} )

Therefore, substituting these values gives:

P(Exactly2Tennis)=3×(18)2×(78)P(Exactly 2 Tennis) = 3 \times \left( \frac{1}{8} \right)^2 \times \left( \frac{7}{8} \right)

Calculating this yields:

=215120.04101= \frac{21}{512} \approx 0.04101

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