The closed line segment [0, 1] is shown below - Leaving Cert Mathematics - Question 7 - 2019
Question 7
The closed line segment [0, 1] is shown below. The first three steps in the construction of the Cantor Set are also shown:
- Step 1 removes the open middle third of... show full transcript
Worked Solution & Example Answer:The closed line segment [0, 1] is shown below - Leaving Cert Mathematics - Question 7 - 2019
Step 1
Complete the table below to show the length of the line segment(s) removed at each step for the first 5 steps.
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Answer
Step
1
2
3
4
5
Length Removed
rac{1}{3}
rac{1}{9}
rac{1}{27}
rac{1}{81}
rac{1}{243}
Step 2
Find the total length of all of the line segments removed from the initial line segment of length 1 unit, after a finite number (n) of steps in the process.
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Answer
To find the total length removed after n steps, we note that at each step, we remove segments of length which can be described as a geometric series. The length removed at the nth step is:
Complete the table below to identify the end-points labelled in the diagram.
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Answer
Label
A
B
C
D
E
F
End-point
0
rac{1}{3}
rac{2}{3}
1
0
1
Step 5
Give a reason why $rac{1}{3} + rac{1}{27} + rac{1}{81}$ is a point in the Cantor Set.
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Answer
The sum rac{1}{3} + rac{1}{27} + rac{1}{81} corresponds to segments that remain after removing the middle thirds in the construction of the Cantor Set. As these points are in the remaining segments, they are included in the Cantor Set.
Step 6
The limit of the series $rac{1}{3} + rac{1}{27} + rac{1}{243} + ullet ullet ullet$ is a point in the Cantor Set. Find this point.
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Answer
The limit of the series rac{1}{3} + rac{1}{27} + rac{1}{243} + ullet ullet ullet can be identified as:
S_{ ext{limit}} = rac{1}{3} imes rac{1}{1 - rac{1}{9}} = rac{1}{3} imes rac{9}{8} = rac{3}{8}.
This point is in the Cantor Set.
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