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In a class of 30 students, 20 study Physics, 6 study Biology and 4 study both Physics and Biology - Leaving Cert Mathematics - Question b - 2013

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In a class of 30 students, 20 study Physics, 6 study Biology and 4 study both Physics and Biology. (i) Represent the information on the Venn Diagram. A student is ... show full transcript

Worked Solution & Example Answer:In a class of 30 students, 20 study Physics, 6 study Biology and 4 study both Physics and Biology - Leaving Cert Mathematics - Question b - 2013

Step 1

By calculating probabilities, investigate if the events E and F are independent.

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Answer

To investigate if events E (the student studies Physics) and F (the student studies Biology) are independent, we apply the definition of independent events:

  1. Calculating P(E and F): This represents the probability that a student studies both Physics and Biology. From the Venn Diagram, there are 4 students studying both subjects out of 30 total students.

    P(EF)=430=215P(E \cap F) = \frac{4}{30} = \frac{2}{15}

  2. Calculating P(E): This is the probability that a student studies Physics.

    • From our calculations:

    P(E)=2030=23P(E) = \frac{20}{30} = \frac{2}{3}

  3. Calculating P(F): This is the probability that a student studies Biology.

    • From our earlier calculations:

    P(F)=630=15P(F) = \frac{6}{30} = \frac{1}{5}

  4. Calculating P(E) x P(F):

    P(E)×P(F)=(23)×(15)=215P(E) \times P(F) = \left(\frac{2}{3}\right) \times \left(\frac{1}{5}\right) = \frac{2}{15}

  5. Comparison:

    • Now, we check if P(EF)=P(E)×P(F)P(E \cap F) = P(E) \times P(F):

    Since: P(EF)=215P(E \cap F) = \frac{2}{15} and P(E)×P(F)=215P(E) \times P(F) = \frac{2}{15} We conclude:

    Events E and F are independent events.

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