Acme Confectionery has launched a new bar called Chocolate Crunch - Leaving Cert Mathematics - Question 8 - 2018
Question 8
Acme Confectionery has launched a new bar called Chocolate Crunch. The weights of these new bars are normally distributed with a mean of 64.6 g and a standard deviat... show full transcript
Worked Solution & Example Answer:Acme Confectionery has launched a new bar called Chocolate Crunch - Leaving Cert Mathematics - Question 8 - 2018
Step 1
Find the probability that the mean weight of the sample is between 4.6 g and 4.7 g.
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Answer
To find this probability, we will use the Z-score formula:
Now, for a 95% confidence interval, the Z-score is approximately 1.96. Thus, the margin of error (ME) is:
ME=ZimesSE=1.96×0.025≈0.049
Now we find the confidence interval:
0.81−0.049≤p≤0.81+0.049
So,
0.76≤p≤0.86
The 95% confidence interval for the population proportion who liked the new bar is (0.76, 0.86).
Step 3
Put one tick into the table for each statement.
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Answer
When forming confidence intervals (for fixed n and (\hat{p})), an increased confidence level implies a wider interval.
-> Always True.
As the value of (\hat{p}) increases (for fixed n), the estimated standard error of the population proportion increases.
-> Sometimes True.
As the value of (\hat{p}(1 - \hat{p})) increases (for fixed n), the estimated standard error of the population proportion increases.
-> Sometimes True.
As n, the number of people sampled, increases (for fixed (\hat{p})), the estimated standard error of the population proportion increases.
-> Never True.
Step 4
Using calculus or otherwise, find the maximum value of \(\hat{p}(1 - \hat{p})\).
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Answer
We can express the function as:
M=p^(1−p^)=p^−p^2
To find the maximum value, we differentiate:
dp^dM=1−2p^=0
Solving for (\hat{p}):
p^=21
Now, substituting back into the original equation:
Mmax=21(1−21)=41=0.25
Thus, the maximum value of (\hat{p}(1 - \hat{p})) is 0.25.
Step 5
Find the largest possible value of the radius of the 95% confidence interval.
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Answer
Using the result from the previous part, we substitute into:
R=1.96n0.25
For a sample size of 800:
R=1.968000.25=1.96×0.0177≈0.0347
Hence, the largest possible radius of the 95% confidence interval for a population proportion, given a random sample of size 800, is approximately 0.0347.
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