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An experiment measures the fuel consumption at various speeds for a particular model of car - Leaving Cert Mathematics - Question 2 - 2017

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An experiment measures the fuel consumption at various speeds for a particular model of car. The data collected are shown in Table 1 below. Table 1 Speed (km/hour)... show full transcript

Worked Solution & Example Answer:An experiment measures the fuel consumption at various speeds for a particular model of car - Leaving Cert Mathematics - Question 2 - 2017

Step 1

Find the correlation coefficient of the data in Table 1, correct to 3 decimal places.

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Answer

To find the correlation coefficient, we will use the formula for Pearson's correlation coefficient, given by:

r = rac{n( ext{Σ}xy) - ( ext{Σ}x)( ext{Σ}y)}{ ext{√}[n( ext{Σ}x^2) - ( ext{Σ}x)^2][n( ext{Σ}y^2) - ( ext{Σ}y)^2]}

Where:

  • nn is the number of data points
  • xx is the speed
  • yy is the fuel consumption

Calculating each component from the data:

  • n=7n = 7
  • extΣx=40+48+56+64+88+96+112=504 ext{Σ}x = 40 + 48 + 56 + 64 + 88 + 96 + 112 = 504
  • extΣy=21+16+18+16+13+11+9=105 ext{Σ}y = 21 + 16 + 18 + 16 + 13 + 11 + 9 = 105
  • extΣxy=(4021)+(4816)+(5618)+(6416)+(8813)+(9611)+(1129)=1716 ext{Σ}xy = (40*21) + (48*16) + (56*18) + (64*16) + (88*13) + (96*11) + (112*9) = 1716
  • extΣx2=402+482+562+642+882+962+1122=27936 ext{Σ}x^2 = 40^2 + 48^2 + 56^2 + 64^2 + 88^2 + 96^2 + 112^2 = 27936
  • extΣy2=212+162+182+162+132+112+92=2673 ext{Σ}y^2 = 21^2 + 16^2 + 18^2 + 16^2 + 13^2 + 11^2 + 9^2 = 2673

Plugging these into the equation gives: r = rac{7(1716) - (504)(105)}{ ext{√}[7(27936) - (504)^2][7(2673) - (105)^2]}

After calculating, we find that: rextisapproximately0.957r ext{ is approximately } -0.957

Step 2

Plot the points from the table on the grid below and draw the line of best fit (by eye).

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Answer

To plot the points:

  1. On a graph, label the x-axis as 'Speed (km/h)' and the y-axis as 'Fuel consumption (km/litre)'.
  2. Plot each point from Table 1 based on the speed and fuel consumption values.
  3. Draw a line of best fit that represents the trend of the data; this should show a downward slope indicating that as speed increases, fuel consumption decreases.

Step 3

The slope of the line of best fit is found to be -0.15. What does this value represent in the context of the data?

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Answer

The slope of the line of best fit being -0.15 indicates that for each increase of 1 km/h in speed, the average distance traveled on 1 litre of fuel decreases by 0.15 km. This suggests an inverse relationship between speed and fuel efficiency; as speed increases, fuel consumption becomes less efficient.

Step 4

Find how much longer it took Mary to complete the journey. Give your answer correct to the nearest minute.

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Answer

To calculate the time taken for both journeys:

  • For Mary: ext{Time} = rac{Distance}{Speed} = rac{260 ext{ km}}{96 ext{ km/h}} = 2.7083 ext{ hours}
  • For Jane: ext{Time} = rac{Distance}{Speed} = rac{260 ext{ km}}{112 ext{ km/h}} = 2.3214 ext{ hours}

Finding the difference in time: extDifference=2.70832.3214=0.3869exthours ext{Difference} = 2.7083 - 2.3214 = 0.3869 ext{ hours}

Convert to minutes: 0.3869exthoursimes60extminutes/hourextisapproximately23.21extminutes0.3869 ext{ hours} imes 60 ext{ minutes/hour} ext{ is approximately } 23.21 ext{ minutes}

Thus, it took Mary about 23 minutes longer.

Step 5

Based on the data in Table 1 and their average speeds, find how much more Jane spent on fuel during the course of this journey.

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Answer

To calculate fuel consumption for each:

  • For Mary (at 96 km/h): From Table 1, fuel consumption is 11 km/litre. Therefore for 260 km: ext{Fuel used} = rac{260}{11} ext{ litres} ext{ and at } 132.9 ext{ cents/litre } Total cost for Mary: ext{Cost} = rac{260}{11} imes 132.9 = ext{approximately } 313.645 ext{ cents}

  • For Jane (at 112 km/h): Fuel consumption is 9 km/litre. Therefore for 260 km: ext{Fuel used} = rac{260}{9} ext{ litres} Total cost for Jane: ext{Cost} = rac{260}{9} imes 132.9 = ext{approximately } 419.24 ext{ cents}

Difference in spending: extDifference=419.24313.645=extapproximately105.595extcents ext{Difference} = 419.24 - 313.645 = ext{approximately } 105.595 ext{ cents}

Thus, Jane spent about 105.60 cents more than Mary.

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