Photo AI

The square ABCD has sides of length 7 cm - Leaving Cert Mathematics - Question 5 - 2018

Question icon

Question 5

The-square-ABCD-has-sides-of-length-7-cm-Leaving Cert Mathematics-Question 5-2018.png

The square ABCD has sides of length 7 cm. The vertices of the square PQRS lie on the perimeter of ABCD, as shown in the diagram, with |AQ| = 5 cm. Find the area of t... show full transcript

Worked Solution & Example Answer:The square ABCD has sides of length 7 cm - Leaving Cert Mathematics - Question 5 - 2018

Step 1

Find the area of the square PQRS

96%

114 rated

Answer

To find the area of square PQRS, we first calculate the area of square ABCD:

extAreaofABCD=7imes7=49extcm2 ext{Area of ABCD} = 7 imes 7 = 49 ext{ cm}^2

Next, we find the area of triangle AQP. The length |AQ| is given as 5 cm, and since PQRS is inside square ABCD, we can find the dimensions of AQ and PQ:

  • The height of triangle AQP can be calculated as the length of AD minus |AQ|, which is: AP=75=2extcm|AP| = 7 - 5 = 2 ext{ cm}

The area of triangle AQP is:

extAreaofAQP=12×base×height=12×5×2=5extcm2 ext{Area of } AQP = \frac{1}{2} \times base \times height = \frac{1}{2} \times 5 \times 2 = 5 ext{ cm}^2

Now, we can find the area of square PQRS:

extAreaofPQRS=extAreaofABCD4×extAreaofAQP ext{Area of PQRS} = ext{Area of ABCD} - 4 \times ext{Area of AQP} =494×5=29extcm2= 49 - 4 \times 5 = 29 ext{ cm}^2

Step 2

Find the circumference of circles u and v

99%

104 rated

Answer

For circle u:

  • The radius is 4 cm.
  • The circumference is given by:

Cu=2πr=2π(4)=8πextcmC_u = 2\pi r = 2\pi(4) = 8\pi ext{ cm}

For circle v:

  • The radius is 6 cm.
  • The circumference is given by:

Cv=2πr=2π(6)=12πextcmC_v = 2\pi r = 2\pi(6) = 12\pi ext{ cm}

Step 3

Find the number of complete rotations wheel u makes

96%

101 rated

Answer

Since the wheels u and v are in non-slip contact, the distance traveled by each wheel is equal when one completes a certain number of rotations.

If wheel v completes 100 rotations:

The distance traveled by wheel v:

Dv=100×Cv=100×12π=1200πextcmD_v = 100 \times C_v = 100 \times 12\pi = 1200\pi ext{ cm}

Now we find the number of rotations wheel u makes:

Let x be the number of complete rotations made by wheel u:

This distance is equal to:

Du=x×Cu=x×8πD_u = x \times C_u = x \times 8\pi

Setting these equal gives:

100×12π=x×8π100 \times 12\pi = x \times 8\pi

Divide each side by π\pi and solve for x:

1200=8x1200 = 8x

Thus,

x=12008=150x = \frac{1200}{8} = 150

Therefore, wheel u makes 150 complete rotations.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;