The diagram below shows the graph of the function $f : x \mapsto \sin 2x$ - Leaving Cert Mathematics - Question 5 - 2014
Question 5
The diagram below shows the graph of the function $f : x \mapsto \sin 2x$. The line $2y = 1$ is also shown.
(a) On the same diagram above, sketch the graphs of $g ... show full transcript
Worked Solution & Example Answer:The diagram below shows the graph of the function $f : x \mapsto \sin 2x$ - Leaving Cert Mathematics - Question 5 - 2014
Step 1
On the same diagram above, sketch the graphs of $g : x \mapsto \sin x$ and $h : x \mapsto 3\sin 2x$. Indicate clearly which is $g$ and which is $h$.
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Answer
To sketch the graphs of the functions:
Graph of g:x↦sinx:
This is a standard sine wave oscillating between -1 and 1 with a period of 2π. It crosses the x-axis at integer multiples of π.
Graph of h:x↦3sin2x:
This function oscillates between -3 and 3 due to the amplitude of 3, and it has a period of π because the frequency is doubled (2 in front of x). It also crosses the x-axis at x=2nπ where n is any integer.
Indicate the functions:
Use different colors for clarity: let g be in green and h in red. Clearly label both graphs on the diagram.
Step 2
Find the co-ordinates of the point $P$ in the diagram.
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Answer
To find the coordinates of point P which is the intersection of the line y=21 and the curve y=sin2x:
Setting up the equation:
Set sin2x=21.
Solving for x:
The general solution for sinθ=21 is θ=6π+2nπ or θ=65π+2nπ, where n∈Z.
For θ=2x, we have:
2x=6π+2nπ
This gives x=12π+nπ
2x=65π+2nπ
This gives x=125π+nπ
Finding suitable x values:
Since we are considering x in the range [0,2π], the valid values from these solutions are:
x=12π,125π,1213π,1217π.
Identifying the y-coordinate of point P:
The y-coordinate is clearly 21 since point P lies on the line y=21.
Thus, the coordinates of point P are:
o (1217π,21).
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