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A car starts from rest and has an acceleration of 6 m/s² - Leaving Cert Physics - Question (b) - 2021

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Question (b)

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A car starts from rest and has an acceleration of 6 m/s². Calculate the distance it travels in 12 s.

Worked Solution & Example Answer:A car starts from rest and has an acceleration of 6 m/s² - Leaving Cert Physics - Question (b) - 2021

Step 1

Identify the Given Variables

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Answer

We know the following variables:

  • Initial velocity (uu) = 0 m/s (the car starts from rest)
  • Acceleration (aa) = 6 m/s²
  • Time (tt) = 12 s

Step 2

Use the Equation of Motion

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Answer

The equation to calculate distance (ss) when starting from rest is:

s=ut+12at2s = ut + \frac{1}{2} a t^2 Substituting the known values:

s=012+12(6)(12)2s = 0 \cdot 12 + \frac{1}{2} (6) (12)^2

Step 3

Calculate Distance

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Answer

Now we can simplify the equation:

s=0+12(6)(144)s = 0 + \frac{1}{2} (6) (144) s=3144=432ms = 3 \cdot 144 = 432 m

Step 4

Final Answer

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Answer

The distance traveled by the car in 12 seconds is 432 meters.

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