The diagram shows a circuit used to investigate the variation of current with potential difference for a filament lamp - Leaving Cert Physics - Question 4 - 2011
Question 4
The diagram shows a circuit used to investigate the variation of current with potential difference for a filament lamp.
(i) Name the instrument X. What does it meas... show full transcript
Worked Solution & Example Answer:The diagram shows a circuit used to investigate the variation of current with potential difference for a filament lamp - Leaving Cert Physics - Question 4 - 2011
Step 1
Name the instrument X. What does it measure?
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Answer
The instrument X is a voltmeter. It measures the potential difference (voltage) across the filament lamp in volts.
Step 2
Name the component V. What does it do?
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The component V is a rheostat (or variable resistor). It adjusts the resistance in the circuit, thereby controlling the current flowing through the circuit and the filament lamp.
Step 3
Draw a graph, on graph paper, of the current against the potential difference.
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To plot the graph:
Label the x-axis as 'Potential Difference (V)' and the y-axis as 'Current (A)'.
Plot the points from the table:
(2, 0.9)
(4, 1.6)
(6, 2.1)
(7, 2.5)
(8, 2.8)
(9, 3.0)
Draw a smooth curve through the points to represent the relationship.
Make sure to correctly label the axes and ensure the points are reasonably spaced.
Step 4
What does your graph tell you about the variation of current with potential difference for a filament lamp?
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The graph indicates that the current increases with potential difference, but not in a linear fashion. This suggests that the filament lamp does not follow Ohm's Law at higher voltages, as the resistance increases with temperature. This is characteristic of non-ohmic materials.
Step 5
Using your graph, calculate the resistance of the lamp when the potential difference across the lamp is 5.5 V.
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To calculate the resistance (R) using Ohm's Law: R=IV
From the graph, at V = 5.5 V, estimate the current (I) to be approximately 2.1 A. Then, substituting the values gives:
R=2.15.5≈2.62Ω
Thus, the resistance of the lamp at 5.5 V is approximately 2.62 ohms.
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