A hair dryer with a plastic casing uses a coiled wire as a heat source - Leaving Cert Physics - Question 8 - 2010
Question 8
A hair dryer with a plastic casing uses a coiled wire as a heat source.
When an electric current flows through the coiled wire, the air around it heats up and a mot... show full transcript
Worked Solution & Example Answer:A hair dryer with a plastic casing uses a coiled wire as a heat source - Leaving Cert Physics - Question 8 - 2010
Step 1
What is an electric current?
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Answer
An electric current is the flow of electric charge, typically carried by moving electrons in a conductor.
Step 2
Give two other effects of an electric current.
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Magnetic effect: An electric current generates a magnetic field around the conductor.
Chemical effect: An electric current can cause chemical reactions, such as electrolysis.
Step 3
(i) Describe what happens: (a) when switch A is closed and the rheostat is adjusted
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When switch A is closed, the circuit is completed, allowing current to flow.
Adjusting the rheostat changes the resistance in the circuit, which in turn modifies the speed of the fan by controlling the amount of current flowing to the motor.
Step 4
(i) Describe what happens: (b) when switch A and switch B are closed.
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When both switches A and B are closed, current flows through the heating coil, causing it to generate heat.
At the same time, the fan operates, blowing the heated air out, which aids in drying.
Step 5
(ii) (a) What is the initial resistance of the coil?
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To find the initial resistance of the coil, we use the formula for power: P=I2R
Here, we rearrange it to find R: R=I2P
Assuming a maximum power (P) of 2000 W at 230 V:
The current (I) can be derived from Ohm’s law: I=VP=2302000≈8.7extA
Then, substituting the values: R=(8.7)22000≈26.4Ω
Step 6
(ii) (b) Calculate the current that flows through the coil when the dryer is turned on.
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Using the formula for current: I=VP=230extV2000extW≈8.7extA
Step 7
(iii) Calculate the length of the coil of wire.
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To calculate the length of the wire, use the formula for resistance: R=ρAL
where:
R=26.4Ω
ρ=1.1×10−6Ωm (resistivity of nichrome)
A=πr2, with diameter 0.17 mm so radius r = 0.085 mm = 0.085 \times 10^{-3} m.
Calculating the cross-sectional area: A=π(0.085×10−3)2≈2.27×10−9m2
Thus, substituting into the resistance formula: 26.4=1.1×10−62.27×10−9L
Solving for length L gives: L≈0.5448m or 54.48 cm.
Step 8
(iv) Explain why the current through the coil would decrease if the fan developed a fault and stopped working.
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If the fan stops working, the airflow that helps dissipate the heat generated by the coil diminishes.
Consequently, the coil's temperature rises, increasing its resistance due to the temperature coefficient of resistivity.
Higher resistance leads to a reduction in current, according to Ohm’s law, as the voltage remains constant.
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