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A current-carrying wire of length 20 cm is placed in a magnetic field - Leaving Cert Physics - Question h - 2022

Question h

A current-carrying wire of length 20 cm is placed in a magnetic field. When a current of 55 mA flows in the wire the maximum force it can experience is 130 μN. Calcu... show full transcript

Worked Solution & Example Answer:A current-carrying wire of length 20 cm is placed in a magnetic field - Leaving Cert Physics - Question h - 2022

Step 1

Calculate Force using the Formula F = BIL

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Answer

To calculate the magnetic flux density (B), we can rearrange the formula:

$F = BIL$

Here, we know:

F (the force) = 130 μN = 130 \times 10^{-6} N
I (current) = 55 mA = 0.055 A
L (length of the wire) = 20 cm = 0.2 m

Now, substituting the values into the formula gives us: $B = \frac{F}{IL}$

Step 2

Substitute the Values into the Rearranged Formula

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Answer

We substitute the known values into the formula:

$B = \frac{130 \times 10^{-6}}{0.2 \times 0.055}$

Calculating the denominator first:

$0.2 \times 0.055 = 0.011$

Now substituting back gives: $B = \frac{130 \times 10^{-6}}{0.011}$

Step 3

Calculate the Resulting Magnetic Flux Density

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Answer

Now, performing the final calculation:

$B = \frac{130 \times 10^{-6}}{0.011} \approx 0.0118 T$

Thus, the magnetic flux density of the field is approximately 0.0118 T.

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