Photo AI

In an experiment to measure the wavelength of a monochromatic light source, a narrow beam of light was incident normally on a diffraction grating having 400 lines per mm - Leaving Cert Physics - Question 3 - 2011

Question icon

Question 3

In-an-experiment-to-measure-the-wavelength-of-a-monochromatic-light-source,-a-narrow-beam-of-light-was-incident-normally-on-a-diffraction-grating-having-400-lines-per-mm-Leaving Cert Physics-Question 3-2011.png

In an experiment to measure the wavelength of a monochromatic light source, a narrow beam of light was incident normally on a diffraction grating having 400 lines pe... show full transcript

Worked Solution & Example Answer:In an experiment to measure the wavelength of a monochromatic light source, a narrow beam of light was incident normally on a diffraction grating having 400 lines per mm - Leaving Cert Physics - Question 3 - 2011

Step 1

Name a source of monochromatic light.

96%

114 rated

Answer

A suitable source of monochromatic light is a sodium (Na) lamp or a laser.

Step 2

Describe, with the aid of a diagram, how the data were obtained.

99%

104 rated

Answer

To obtain the data for measuring the angles, the following steps were used:

  1. Set up a monochromatic light source, a spectrometer, and a diffraction grating on a turntable.
  2. Ensure that the light beam is focused on the first image on the left-hand side (l.h.s) scale.
  3. Measure the angle θ using trigonometry with reference to the distance D from the grating to the measurement screen. A diagram representing this setup is crucial for clarity.

Step 3

Using the data, calculate the wavelength of the monochromatic light.

96%

101 rated

Answer

Using the formula for diffraction:

nd=Dimesextsinhetan d = D imes ext{sin} heta

Where:

  • n = order of the image (n=1 for the first image, n=2 for the second image)
  • d = distance between lines on the grating = 1 / 400 mm
  • D = distance to the screen (this is measured) Using the angles:
  • For the first image (θ=14.90°{θ = 14.90°}): d = rac{1}{400} ext{Wavelength } ext{λ} = rac{D imes ext{sin}(θ)}{n} Calculating for average angle yields: extWavelengthextλextapproximatelyequalto642.3extnm ext{Wavelength } ext{λ} ext{ approximately equal to } 642.3 ext{ nm}.

Step 4

What effect would each of the following changes have on the bright images formed:

98%

120 rated

Answer

i) Using a monochromatic light source of longer wavelength:

  • This would result in fewer images or a wider spacing between them, as longer wavelengths lead to less diffraction.

ii) Using a diffraction grating having 200 lines per mm:

  • This would yield smaller or closer images due to increased diffraction effects as it allows for a more substantial interaction with the incoming light.

iii) Using a source of white light instead of monochromatic light:

  • In this scenario, each fringe/image would represent a spectrum formed due to the different wavelengths present in white light, leading to the overlapping of colors which could blur the bright images.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;