Photo AI

What is meant by the term 'acceleration due to gravity'? A spacecraft of mass 800 kg is on the surface of the moon, where the acceleration due to gravity is 1.6 m s² - Leaving Cert Physics - Question 6 - 2012

Question icon

Question 6

What-is-meant-by-the-term-'acceleration-due-to-gravity'?--A-spacecraft-of-mass-800-kg-is-on-the-surface-of-the-moon,-where-the-acceleration-due-to-gravity-is-1.6-m-s²-Leaving Cert Physics-Question 6-2012.png

What is meant by the term 'acceleration due to gravity'? A spacecraft of mass 800 kg is on the surface of the moon, where the acceleration due to gravity is 1.6 m s... show full transcript

Worked Solution & Example Answer:What is meant by the term 'acceleration due to gravity'? A spacecraft of mass 800 kg is on the surface of the moon, where the acceleration due to gravity is 1.6 m s² - Leaving Cert Physics - Question 6 - 2012

Step 1

What is meant by the term 'acceleration due to gravity'?

96%

114 rated

Answer

The term 'acceleration due to gravity' refers to the acceleration experienced by an object due to the gravitational pull of a celestial body, such as a planet or moon. It is the rate at which an object gains speed when falling freely under the influence of gravity. For instance, on Earth, this acceleration is approximately 9.8 m/s², while on the Moon, it is 1.6 m/s².

Step 2

Draw a diagram showing the forces acting on the module at lift-off.

99%

104 rated

Answer

A diagram should illustrate the module with arrows indicating the following forces:

  • Weight (downward): Calculated as the gravitational force on the module, which is the mass times the acceleration due to gravity on the Moon (600 kg * 1.6 m/s²).
  • Thrust (upward): The upward force exerted by the engine, which is given as 2000 N.

Step 3

What is the resultant force on the module?

96%

101 rated

Answer

The resultant force (F) is calculated by subtracting the weight from the thrust:

F=ThrustWeightF = Thrust - Weight

Here, Weight = 600 kg * 1.6 m/s² = 960 N.

Thus, the resultant force is:

F=2000N960N=1040NF = 2000 N - 960 N = 1040 N

Step 4

Calculate the acceleration of the module during lift-off.

98%

120 rated

Answer

To find the acceleration (a) of the module, we use Newton's second law, which states:

F=maF = ma

Rearranging gives:

a=Fma = \frac{F}{m}

Here, F is the resultant force (1040 N) and m is the mass of the module (600 kg):

a=1040N600kg=1.73m/s2a = \frac{1040 N}{600 kg} = 1.73 m/s²

Step 5

Calculate the velocity of the module, 20 seconds after lift-off.

97%

117 rated

Answer

Using the equation of motion:

v=u+atv = u + at

Where:

  • Initial velocity (u) is 0 (since it starts from rest).
  • a is the acceleration calculated as 1.73 m/s².
  • t is the time, which is 20 s.

So, v=0+(1.73m/s220s)=34.6m/sv = 0 + (1.73 m/s² * 20 s) = 34.6 m/s

Step 6

Would the engine of the module be able to lift it off the earth's surface? Justify your answer in terms of the forces acting on the module.

97%

121 rated

Answer

The engine would not be able to lift the module off the earth's surface, as the weight of the module on Earth is much greater than the thrust produced by the engine. The weight can be calculated as:

Weight=mg=(600kg)(9.8m/s2)=5880NWeight = mg = (600 kg)(9.8 m/s²) = 5880 N

Since the thrust (2000 N) is less than the weight (5880 N), the engine could not overcome gravitational force on Earth.

Step 7

Why is the acceleration due to gravity on the moon less than the acceleration due to gravity on earth?

96%

114 rated

Answer

The acceleration due to gravity on a celestial body depends on its mass and radius. The moon has significantly less mass and a smaller radius than Earth, resulting in a reduced gravitational pull. Therefore, the gravitational acceleration on the Moon is only 1.6 m/s² compared to Earth's 9.8 m/s².

Step 8

Suggest a reason why the module of the spacecraft when launched from the moon does not need a streamlined shape like those that are launched from earth.

99%

104 rated

Answer

The module does not need a streamlined shape because the Moon has a very thin atmosphere compared to Earth. The lack of significant air resistance means that aerodynamic drag is minimal during launch; therefore, a streamlined shape is not necessary to reduce drag, unlike spacecraft launched from Earth.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;