The temperature of an object is measured using a thermometer, which is based on the variation of its thermometric property - Leaving Cert Physics - Question 7 - 2008
Question 7
The temperature of an object is measured using a thermometer, which is based on the variation of its thermometric property.
(i) What is meant by temperature?
(ii) ... show full transcript
Worked Solution & Example Answer:The temperature of an object is measured using a thermometer, which is based on the variation of its thermometric property - Leaving Cert Physics - Question 7 - 2008
Step 1
What is meant by temperature?
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Answer
Temperature is a measure of the average kinetic energy of the particles in an object. It indicates how hot or cold an object is and determines the direction of heat transfer between objects.
Step 2
What is the unit of temperature?
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The unit of temperature in the SI system is the Kelvin (K), but degrees Celsius (°C) is also commonly used.
Step 3
Give an example of a thermometric property.
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An example of a thermometric property is the resistance of a thermistor, which changes with temperature.
Step 4
What is heat?
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Heat is a form of energy that is transferred between two objects due to a temperature difference. It flows from the hotter object to the cooler one.
Step 5
Name three ways in which heat can be transferred.
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Conduction: the transfer of heat through direct contact between materials.
Convection: the transfer of heat through the movement of fluids (liquids or gases).
Radiation: the transfer of heat in the form of electromagnetic waves.
Step 6
Define specific heat capacity.
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Specific heat capacity is defined as the amount of heat energy required to raise the temperature of 1 kg of a material by 1 Kelvin (or 1 °C). The formula is given by:
c=mΔTQ
where c is the specific heat capacity, Q is the heat added, m is the mass, and ΔT is the change in temperature.
Step 7
the rise in temperature of the water;
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The rise in temperature can be calculated as:
ΔT=100°C−20°C=80°C
Step 8
the energy required to heat the water to 100 °C;
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Answer
Using the formula:
Q=mcΔT
Substituting the values:
Mass (m) = 0.5 kg
Specific heat capacity (c) = 4200 J/kg·K
Change in temperature (ΔT) = 80 °C
We get:
Q=0.5×4200×80=168000J
Step 9
the amount of energy the ring supplies every second;
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Power (P) is given as 2 kW, which can be converted to watts (1 kW = 1000 W):
P=2 kW=2000W
Step 10
the time it will take to heat the water to 100 °C.
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Answer
The time can be calculated using:
t=PQ
Substituting the values:
Q=168000J
P=2000W
We get:
t=2000168000=84s
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