Calculate the refractive index of the glass block shown in the diagram - Leaving Cert Physics - Question b - 2018
Question b
Calculate the refractive index of the glass block shown in the diagram.
The angles given in the diagram are:
- Angle of incidence (in air): 40°
- Angle of refractio... show full transcript
Worked Solution & Example Answer:Calculate the refractive index of the glass block shown in the diagram - Leaving Cert Physics - Question b - 2018
Step 1
Identify the known values
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Answer
From the diagram, we have:
Angle of incidence, heta1=40°
Angle of refraction, heta2=25°
Refractive index of air, n1=1 (approximately)
Step 2
Apply Snell's Law
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Answer
Snell's Law states:
n1imesextsin(heta1)=n2imesextsin(heta2)
We can rearrange this to find the refractive index of glass, n2:
n_2 = rac{n_1 imes ext{sin}( heta_1)}{ ext{sin}( heta_2)}
Step 3
Substitute the values into the equation
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Answer
Substituting the values into the equation:
n_2 = rac{1 imes ext{sin}(40°)}{ ext{sin}(25°)}
Step 4
Calculate the refractive index
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Answer
Using a calculator, we find:
extsin(40°)≈0.6428
extsin(25°)≈0.4226
Thus:
n_2 = rac{0.6428}{0.4226} \approx 1.52
The refractive index of the glass block is approximately 1.52.
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