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Calculate the refractive index of the glass block shown in the diagram - Leaving Cert Physics - Question b - 2018

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Calculate the refractive index of the glass block shown in the diagram. The angles given in the diagram are: - Angle of incidence (in air): 40° - Angle of refractio... show full transcript

Worked Solution & Example Answer:Calculate the refractive index of the glass block shown in the diagram - Leaving Cert Physics - Question b - 2018

Step 1

Identify the known values

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Answer

From the diagram, we have:

  • Angle of incidence, heta1=40° heta_1 = 40°
  • Angle of refraction, heta2=25° heta_2 = 25°
  • Refractive index of air, n1=1n_1 = 1 (approximately)

Step 2

Apply Snell's Law

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Snell's Law states: n1imesextsin(heta1)=n2imesextsin(heta2)n_1 imes ext{sin}( heta_1) = n_2 imes ext{sin}( heta_2)

We can rearrange this to find the refractive index of glass, n2n_2: n_2 = rac{n_1 imes ext{sin}( heta_1)}{ ext{sin}( heta_2)}

Step 3

Substitute the values into the equation

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Answer

Substituting the values into the equation: n_2 = rac{1 imes ext{sin}(40°)}{ ext{sin}(25°)}

Step 4

Calculate the refractive index

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Using a calculator, we find:

  • extsin(40°)0.6428 ext{sin}(40°) \approx 0.6428
  • extsin(25°)0.4226 ext{sin}(25°) \approx 0.4226

Thus: n_2 = rac{0.6428}{0.4226} \approx 1.52

The refractive index of the glass block is approximately 1.52.

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